将输出写入 Azure Functions 中的 Blob

Question

我正在学习使用 Azure 函数。所以，我可能听起来很愚蠢。我正在编写一个计时器触发函数，该函数每 1 分钟运行一次，添加两个数字并写入文件。这工作正常，因为我可以将输出写入本地服务器上的文件。

第二步，我想将输出写入 blob。下面是代码：

import datetime
import logging  
import azure.functions as func

a=4
b=5
sum=a+b
file_name= open("sum.txt","w+")


def main(mytimer: func.TimerRequest, outputBlob: func.Out[str]) -> None:
    utc_timestamp = datetime.datetime.utcnow().replace(
        tzinfo=datetime.timezone.utc).isoformat()
    if mytimer.past_due:
        global sum
        global file_name
        print("sum:", sum)
        logging.info('The sum has been calculated!')



    logging.info(sum)
    logging.info('Python timer trigger function ran at %s', utc_timestamp)
    with open("sum.txt", "a") as file_name:
        file_name.seek(0)
        file_name.write("\n")
        file_name.write("Sum: %s" % sum)

    outputBlob.set(file_name)

但是，当我运行该函数时，出现以下错误：

[10/02/2020 14:06:00] Executed 'Functions.CalcPayment' (Failed, Id=547f7a3d-03b4-4a02-98e7-f4bfb73e6f5e)
[10/02/2020 14:06:00] System.Private.CoreLib: Exception while executing function: Functions.CalcPayment. System.Private.CoreLib: Result: Failure
[10/02/2020 14:06:00] Exception: TypeError: unable to encode outgoing TypedData: unsupported type "<class 'azure_functions_worker.bindings.generic.GenericBinding'>" for Python type "int"
[10/02/2020 14:06:00] Stack:   File "/usr/local/Cellar/azure-functions-core-tools@3/3.0.2106/workers/python/3.7/OSX/X64/azure_functions_worker/dispatcher.py", line 330, in _handle__invocation_request
[10/02/2020 14:06:00]     pytype=out_type_info.pytype)
[10/02/2020 14:06:00]   File "/usr/local/Cellar/azure-functions-core-tools@3/3.0.2106/workers/python/3.7/OSX/X64/azure_functions_worker/bindings/meta.py", line 83, in to_outgoing_proto
[10/02/2020 14:06:00]     f'unable to encode outgoing TypedData: '
[10/02/2020 14:06:00] .

Answer 1

您不需要写入文件，只需创建一个对您的情况有意义的字符串并将其推送到输出变量即可。您可以使用此示例作为起点。