如何获得proc_open()的输出

Question

我试图从proc_openphp中获取方法的输出,但是,当我打印它时,我变空了.

$descriptorspec = array(
    0 => array("pipe", "r"),
    1 => array("pipe", "w"),
    2 => array("file", "files/temp/error-output.txt", "a")
);

$process = proc_open("time ./a  a.out", $descriptorspec, $pipes, $cwd);

只要我知道,我可以得到输出 stream_get_contents()

echo stream_get_contents($pipes[1]);
fclose($pipes[1]);

但我不能这样做......有什么建议吗？

先谢谢......

Answer 1

您的代码或多或少对我有用. time打印输出,stderr如果您正在寻找输出,请查看您的文件files/temp/error-output.txt.该stdout管道$pipes[1]将只包含该程序的输出./a.

我的责备:

[edan@edan tmp]$ cat proc.php 

<?php

$cwd='/tmp';
$descriptorspec = array(
    0 => array("pipe", "r"),
    1 => array("pipe", "w"),
    2 => array("file", "/tmp/error-output.txt", "a") );

$process = proc_open("time ./a a.out", $descriptorspec, $pipes, $cwd);

echo stream_get_contents($pipes[1]);
fclose($pipes[1]);

?>

[edan@edan tmp]$ php proc.php 

a.out here.

[edan@edan tmp]$ cat /tmp/error-output.txt

real    0m0.001s
user    0m0.000s
sys     0m0.002s

Answer 2

这是另一个例子proc_open().我在这个例子中使用Win32 ping.exe命令.CMIIW

set_time_limit(1800);
ob_implicit_flush(true);

$exe_command = 'C:\\Windows\\System32\\ping.exe -t google.com';

$descriptorspec = array(
    0 => array("pipe", "r"),  // stdin
    1 => array("pipe", "w"),  // stdout -> we use this
    2 => array("pipe", "w")   // stderr 
);

$process = proc_open($exe_command, $descriptorspec, $pipes);

if (is_resource($process))
{

    while( ! feof($pipes[1]))
    {
        $return_message = fgets($pipes[1], 1024);
        if (strlen($return_message) == 0) break;

        echo $return_message.'<br />';
        ob_flush();
        flush();
    }
}

希望这有助于=)