Moa*_*oak 4 zend-framework zend-auth
这似乎是一个愚蠢的问题,但在这段代码中,我将在哪里插入条件 'WHERE state=1'
public function loginByUsernameAndPassword($username, $password)
{
$this->_auth_adapter = new Zend_Auth_Adapter_DbTable( $this->getAdapter() );
$this->_auth_adapter->setTableName('zend_administration_user')
->setIdentityColumn('user_nm')
->setCredentialColumn('password')
->setCredentialTreatment('SHA1(CONCAT(?,salt))');
$this->_auth_adapter->setIdentity($username)
->setCredential($password);
$result = Zend_Auth::getInstance()->authenticate($this->_auth_adapter);
return $result->isValid();
}
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基于zf手册中的示例,我想说你可以添加AND state=1到你的setCredentialTreatment()方法中:
->setCredentialTreatment('SHA1(CONCAT(?,salt)) AND state = 1');
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