Pol*_*ina 2 javascript arrays object
我有这样的数据:
Run Code Online (Sandbox Code Playgroud)const bigData = [ { id: '1', data: [ {category: 'swim', value: 'Abc'}, {category: 'ran', value: '123'}, {category: 'play', value: 'Test'} ] }, { id: '2', data: [ {category: 'swim', value: 'Abc'}, {category: 'ran', value: ''}, {category: 'play', value: 'abc'} ] }, { id: '3', data: [ {category: 'swim', value: 'String that I Need'}, {category: 'ran', value: '456'}, {category: 'play', value: 'Testtest'} ] } ]
如果此对象之一在其值中包含部分字符串,我想获取对象数组。
例如,如果搜索字符串是“String tha”,它应该返回
[ {
id: '3',
data: [
{category: 'swim', value: 'String that I Need'},
{category: 'ran', value: '456'},
{category: 'play', value: 'Testtest'}
]
}]
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如果搜索字符串是“Abc”,它应该返回
[{
id: '1',
data: [
{category: 'swim', value: 'Abc'},
{category: 'ran', value: '123'},
{category: 'play', value: 'Test'}
]
},
{
id: '2',
data: [
{category: 'swim', value: 'somethinf'},
{category: 'ran', value: ''},
{category: 'play', value: 'Abcd'}
]
},]
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到目前为止,这就是我所拥有的,不确定这是否是正确的方向:
const arr = bigData.map(
(item) => item.data
)
const res = arr
?.map((item) => item.map((e) => e.value))
.filter((i) => i.map((e) => e.includes(search) === true))
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没有理由map()将外部数组分配给每个对象的data成员,因为返回值和输入值具有相同的布局。相反,您在filter()外部 array 上执行 a bigData,它应该保留内部数组成员data满足特定条件的对象。
您可以使用 来检查该条件some(),因为它应用于数组的每个元素,并且您只关心是否存在匹配的元素。
function filterBySearch (search) {
return bigData.filter(
({ data }) => data.some(
({ value }) => value.includes(search)
)
);
}
const bigData = [
{
id: '1',
data: [
{category: 'swim', value: 'Abc'},
{category: 'ran', value: '123'},
{category: 'play', value: 'Test'}
]
},
{
id: '2',
data: [
{category: 'swim', value: 'Abc'},
{category: 'ran', value: ''},
{category: 'play', value: 'abc'}
]
},
{
id: '3',
data: [
{category: 'swim', value: 'String that I Need'},
{category: 'ran', value: '456'},
{category: 'play', value: 'Testtest'}
]
}
];
console.log(filterBySearch('String tha'));
console.log(filterBySearch('Abc'));Run Code Online (Sandbox Code Playgroud)
.as-console-wrapper{max-height:100%!important;}Run Code Online (Sandbox Code Playgroud)