1 sql postgresql group-by having
select osmid,ST_X(shape),ST_Y(shape)
from osmpoints
where (osmpoints.osmid, osmpoints.osmtimestamp)
IN (select osmid,MAX(osmtimestamp)
from osmPoints
GROUP BY osmid
Having MAX(osmtimestamp) <= '2019-09-16T01:23:55Z'
AND osmid in ('4426786454','1861591896','1861591869','1861591895',
'4426786455','2038185115','1861591853','6797739995',
'2299605892','6797739994','1861591898','2038185111','4426786454'));
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当我运行这个查询时,我得到基于 osmid 列的排序行。但我的问题是如何按在 IN 子句中使用的 osmid 的顺序获取行?
您可以使用与此处所示相同的技术:
with input(idlist) as (
values (
array['4426786454','1861591896','1861591869','1861591895',
'4426786455','2038185115','1861591853','6797739995',
'2299605892','6797739994','1861591898','2038185111','4426786454']::text[])
)
select p.osmid,ST_X(shape),ST_Y(shape)
from osmpoints p
cross join input
where (p.osmid, p.osmtimestamp) IN (select osmid,MAX(osmtimestamp)
from osmPoints
cross join input
GROUP BY osmid
Having MAX(osmtimestamp) <= '2019-09-16T01:23:55Z'
AND osmid = any(idlist))
order by array_position(idlist, osmid);
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