hor*_*erd 2 python django amazon-s3 boto3
我正在邮递员中发送一个 excel 文件作为请求,并且需要将其上传到 s3 。我从请求访问该文件并将其发送到 s3。
@api_view(['POST'])
def excel_upload(request):
print("request", request)
excel_file = request.FILES['file']
print("excel_file", excel_file) // this prints the name of the excel file i am sending in request
upload_to_aws(excel_file,'X1excelsheets','s3_file_name')
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这是上传文件到 s3 的函数。
def upload_to_aws(local_file, bucket, s3_file):
s3 = boto3.client('s3', aws_access_key_id=ACCESS_KEY,
aws_secret_access_key=SECRET_KEY)
try:
s3.upload_file(local_file, bucket, s3_file)
print("Upload Successful")
return True
except FileNotFoundError:
print("The file was not found")
return False
except NoCredentialsError:
print("Credentials not available")
return False
uploaded = upload_to_aws('local_file', 'bucket_name', 's3_file_name')
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我正在尝试使用这个特定的帖子
https://medium.com/bilesanmiahmad/how-to-upload-a-file-to-amazon-s3-in-python-68757a1867c6
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把事情做好。错误:ValueError:文件名必须是字符串
我使用AWSCLI进行了配置
S3_BUCKET_NAME = 'YOUR_BUCKET'
s3 = boto3.client('s3')
with open(file, 'rb') as f:
s3.upload_fileobj(f, S3_BUCKET_NAME, file)
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我遇到了同样的错误,所以我只是使用upload_fileobj而不是upload_file。这个对我来说效果很好,你可以试试。
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