ValueError:将文件上传到 s3 存储桶时文件名必须是字符串

hor*_*erd 2 python django amazon-s3 boto3

我正在邮递员中发送一个 excel 文件作为请求,并且需要将其上传到 s3 。我从请求访问该文件并将其发送到 s3。

@api_view(['POST'])
def excel_upload(request):
    print("request", request)
    excel_file = request.FILES['file'] 
    print("excel_file", excel_file) // this prints the name of the excel file i am sending in request
    upload_to_aws(excel_file,'X1excelsheets','s3_file_name')
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这是上传文件到 s3 的函数。

def upload_to_aws(local_file, bucket, s3_file):
    s3 = boto3.client('s3', aws_access_key_id=ACCESS_KEY,
                      aws_secret_access_key=SECRET_KEY)

    try:
        s3.upload_file(local_file, bucket, s3_file)
        print("Upload Successful")
        return True
    except FileNotFoundError:
        print("The file was not found")
        return False
    except NoCredentialsError:
        print("Credentials not available")
        return False


uploaded = upload_to_aws('local_file', 'bucket_name', 's3_file_name')
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我正在尝试使用这个特定的帖子

https://medium.com/bilesanmiahmad/how-to-upload-a-file-to-amazon-s3-in-python-68757a1867c6
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把事情做好。错误:ValueError:文件名必须是字符串

Tra*_*sto 5

我使用AWSCLI进行了配置

S3_BUCKET_NAME = 'YOUR_BUCKET'

s3 = boto3.client('s3')
with open(file, 'rb') as f:
    s3.upload_fileobj(f, S3_BUCKET_NAME, file)
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我遇到了同样的错误,所以我只是使用upload_fileobj而不是upload_file。这个对我来说效果很好,你可以试试。