Use*_*013 6 enums interface typescript
我有一个界面:
interface ISomething {
red: string;
blue: string;
green: string;
}
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是否可以定义代表接口中的键的枚举?
我想得到这样的结果:
enum SomethingKeys {
red = "red",
blue= "blue",
green= "green",
}
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ps:我是ts新手,如果问题不正确,请抱歉。
您可以通过创建带有枚举键的对象来实现其他方法:
enum SomethingKeys {
red = "red",
blue= "blue",
green= "green",
}
type ISomething= Record<SomethingKeys, string>
const a: ISomething = {
[SomethingKeys.blue]: 'blue',
[SomethingKeys.red]: 'red',
[SomethingKeys.green]: 'green',
}
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但我认为你真正需要的不是枚举而是联合类型的键,你定义的keyof。考虑:
interface ISomething {
red: string;
blue: string;
green: string;
}
type Keys = keyof ISomething; // "red" | "blue" | "green"
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当您声明自己是新手时,可以使用字符串文字联合。你不需要枚举。
当你拥有时,Keys你也可以使用它们来创建其他类型
// new object with keys of the original one
type OtherTypeWithTheSameKeys = Record<Keys, number> // type with keys of type Keys
const a: OtherTypeWithTheSameKeys = {
blue: 1,
green: 2,
red: 3
}
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