Tre*_*ter 9 javascript charts chart.js
我有一个数据集,其中最后一个值总是很高。这会导致我的条形图出现问题;几乎所有其他值都很难在不悬停的情况下获得感觉。
这是一个屏幕截图:
这就是我正在努力实现的目标;
所以我的问题; 这在 vanilla Chart.js 中是可能的还是我需要一个插件?如果是这样; 有现有的插件还是我需要自己编写一个?
我也对初始问题的替代解决方案持开放态度。
我已经在互联网上寻找类似的东西,但不幸的是没有太多运气。
您可以使用logarithmic类型yAxis
默认值:线性
https://www.chartjs.org/docs/latest/axes/cartesian/logarithmic.html
var ctx = document.getElementById('myChart');
var myChart = new Chart(ctx, {
type: 'bar',
data: {
labels: ["January", "February", "March", "April", "May", "June"],
datasets: [{
label: "Series 1",
backgroundColor: "rgba(255,99,132,0.2)",
borderColor: "rgba(255,99,132,1)",
borderWidth: 2,
hoverBackgroundColor: "rgba(255,99,132,0.4)",
hoverBorderColor: "rgba(255,99,132,1)",
data: [65, 59, 43, 81, 56, 950],
}]
},
options: {
scales: {
yAxes: [{
type: 'logarithmic',
ticks: {
callback: function(tick, index, ticks) {
return tick.toLocaleString();
}
}
}]
}
}
});Run Code Online (Sandbox Code Playgroud)
<script src="https://cdn.jsdelivr.net/npm/chart.js@2.8.0"></script>
<canvas id="myChart" width="400" height="200"></canvas>Run Code Online (Sandbox Code Playgroud)
优化的蜱虫
50 * (Math.floor(i / 50)), // lower 50
50 * (Math.ceil(i / 50)) // higer 50
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50 * (Math.floor(i / 50)), // lower 50
50 * (Math.ceil(i / 50)) // higer 50
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var ctx = document.getElementById('myChart');
var myChart = new Chart(ctx, {
type: 'bar',
data: {
labels: ["January", "February", "March", "April", "May", "June"],
datasets: [{
label: "Series 1",
backgroundColor: "rgba(255,99,132,0.2)",
borderColor: "rgba(255,99,132,1)",
borderWidth: 2,
hoverBackgroundColor: "rgba(255,99,132,0.4)",
hoverBorderColor: "rgba(255,99,132,1)",
data: [65, 59, 43, 81, 56, 950],
}]
},
options: {
scales: {
yAxes: [{
type: 'logarithmic',
ticks: {
callback: function(tick, index, ticks) {
return tick.toLocaleString();
}
},
afterBuildTicks: function(pckBarChart) {
pckBarChart.ticks = pckBarChart.chart.data.datasets[0].data.flatMap(i => [
50 * (Math.floor(i / 50)), // lower 50
50 * (Math.ceil(i / 50)) // higer 50
])
}
}]
}
}
});Run Code Online (Sandbox Code Playgroud)