C++:Boost:如何检查工作目录中另一个文件夹中是否存在文件夹？

Question

码:

boost::filesystem::path config_folder(Config::CONFIG_FOLDER_NAME);

if( !(boost::filesystem::exists(config_folder)))
{
    std::cout << "Network Config Directory not found...\n";
    std::cout << "Creating folder called " << Config::CONFIG_FOLDER_NAME << "\n";
    boost::filesystem::create_directory(config_folder);
}

if( !(boost::filesystem::exists(boost::format("%s/%s") % config_folder % Config::fmap[Config::current_hash_function]));
{
    std::cout << "This hash has not been configure before...\n";
    std::cout << "Creating folder called " << Config::fmap[Config::current_hash_function] << "\n";
    boost::filesystem::create_directory(boost::format("%s/%s") % config_folder % Config::fmap[Config::current_hash_function]);
}

因此,首先,如果config文件夹不存在,请创建它.(此部分有效)接下来,检查current_hash_function文件夹是否存在,如果不存在,请创建它.(这部分不起作用)

我得到的错误;

src/neural_networks/shared.cpp:41: error: no matching function for call to ‘exists(boost::basic_format<char, std::char_traits<char>, std::allocator<char> >&)’

之所以我在fs中执行boost格式:exists check,是因为我不知道如何创建2级深度的路径

Answer 1

该/操作被重载来连接path的对象.无需显式字符串格式化,也无需担心特定于平台的路径分隔符.

if(!(boost::filesystem::exists(config_folder / Config::fmap[Config::current_hash_function]));

std::string只要另一个是a,操作数就可以是path.