con*_*per 4 c# json.net system.reflection
我有一堂课,如下所述:
public class Employee {
[JsonProperty("emp_id")]
public int Id {get; set;}
[JsonProperty("emp_fname")]
public string Name {get;set;}
[JsonProperty("emp_lname")]
public string LastName {get;set;}
}
Run Code Online (Sandbox Code Playgroud)
在上面的类中,我为序列化分配了 Newtonsoft 属性。
我有一个类对象Employee,现在我想找到该属性JsonProperty并获取该属性的值。
例如,我想获取 JsonProprty 属性名称设置为的属性的值emp_lname
有没有办法使用反射来找到这样的价值?
您可以使用 Json.NET 自己的合约解析器来实现此目的。这样做可以正确处理添加或不[JsonProperty(string name)]添加属性的属性,以及直接应用命名策略或数据协定属性的对象。
首先添加以下方法:
public static partial class JsonExtensions
{
static readonly IContractResolver defaultResolver = JsonSerializer.CreateDefault().ContractResolver;
public static object GetJsonProperty<T>(T obj, string jsonName, bool exact = false, IContractResolver resolver = null)
{
if (obj == null)
throw new ArgumentNullException(nameof(obj));
resolver = resolver ?? defaultResolver;
var contract = resolver.ResolveContract(obj.GetType()) as JsonObjectContract;
if (contract == null)
throw new ArgumentException(string.Format("{0} is not serialized as a JSON object", obj));
var property = contract.Properties.GetProperty(jsonName, exact ? StringComparison.Ordinal : StringComparison.OrdinalIgnoreCase);
if (property == null)
throw new ArgumentException(string.Format("Property {0} was not found.", jsonName));
return property.ValueProvider.GetValue(obj); // Maybe check JsonProperty.Readable first, and throw an exception if not?
}
}
Run Code Online (Sandbox Code Playgroud)
现在你可以这样做:
var employee = new Employee
{
LastName = "last name",
};
Console.WriteLine("Value of {0} is {1}.", "emp_lname",
JsonExtensions.GetJsonProperty(employee, "emp_lname")); // Prints Value of emp_lname is last name.
Run Code Online (Sandbox Code Playgroud)
如果您的应用程序默认使用驼峰式大小写进行 JSON 序列化,则可以像这样传入CamelCasePropertyNamesContractResolverfor :resolver
Console.WriteLine("Value of {0} is {1}.", "emp_lname",
JsonExtensions.GetJsonProperty(employee, "emp_lname", resolver : new CamelCasePropertyNamesContractResolver()));
Run Code Online (Sandbox Code Playgroud)
如果您需要获取给定类型的所有 JSON 属性名称的列表,请参阅从类获取要在查询字符串中使用的 JSON 属性名称列表:
public static partial class JsonExtensions
{
public static string [] PropertyNames(Type type)
{
return PropertyNames(defaultResolver, type);
}
//Taken from this answer /sf/answers/3208066011/
//To /sf/ask/2353120381/
public static string [] PropertyNames(this IContractResolver resolver, Type type)
{
if (resolver == null || type == null)
throw new ArgumentNullException();
var contract = resolver.ResolveContract(type) as JsonObjectContract;
if (contract == null)
return new string[0];
return contract.Properties.Where(p => !p.Ignored).Select(p => p.PropertyName).ToArray();
}
}
Run Code Online (Sandbox Code Playgroud)
演示小提琴在这里。