Lau*_*ell 11 sqlite objective-c count
我正在尝试以下代码来计算我的SQLite数据库表中的行数,但它会引发异常.这是一种更简单的方法吗?
- (void) countRecords {
int rows = 0;
@try {
NSString *dbPath = [self getDBPath];
if (sqlite3_open([dbPath UTF8String], &database) == SQLITE_OK) {
NSString *strSQL;
strSQL = @"SELECT COUNT(*) FROM MYTABLE";
const char *sql = (const char *) [strSQL UTF8String];
sqlite3_stmt *stmt;
if (sqlite3_prepare_v2(database, sql, -1, &stmt, NULL) == SQLITE_OK) {
// THIS IS WHERE IT FAILS:
if (SQLITE_DONE!=sqlite3_step(stmt) ) {
NSAssert1(0,@"Error when counting rows %s",sqlite3_errmsg(database));
} else {
rows = sqlite3_column_int(stmt, 0);
NSLog(@"SQLite Rows: %i", rows);
}
sqlite3_finalize(stmt);
}
sqlite3_close(database);
}
}
@catch (NSException * e) {
NSLog(@"Error Counting");
}
}
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Lau*_*ell 11
我遇到了一个解决方案,使用上面的代码,只需用以下代码替换step语句:
if (sqlite3_step(stmt) == SQLITE_ERROR) {
NSAssert1(0,@"Error when counting rows %s",sqlite3_errmsg(database));
} else {
rows = sqlite3_column_int(stmt, 0);
NSLog(@"SQLite Rows: %i", rows);
}
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小智 5
这通常对我有用
- (NSInteger )numberRecordsForTable:(NSString *)table {
NSInteger numTableRecords = -1;
if (sqlite3_open([self.dbPath UTF8String], &database) == SQLITE_OK) {
NSString *sqlStatement = [NSString stringWithFormat: @"select count(*) from %@", table];
const char *sql = [sqlStatement cStringUsingEncoding:NSUTF8StringEncoding];
if(sqlite3_prepare_v2(database, sql, -1, &sqlClause, NULL) == SQLITE_OK) {
while(sqlite3_step(sqlClause) == SQLITE_ROW) {
numTableRecords = sqlite3_column_int(sqlClause, 0);
}
}
else {
printf("could not prepare statement: %s\n", sqlite3_errmsg(database));
}
}
else {
NSLog(@"Error in Opening Database File");
}
sqlite3_close(database);
return numTableRecords;
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}
HTH