Abb*_*bas 5 firebase firebase-authentication flutter
为什么我的 signOut() 方法没有将 currentUser() 设置为 null?
当我单击主页上的注销时,它会检查 isAuthenticated() 方法,该方法返回用户而不是 null。另外,看看我在 logout() 方法中包含的两个注释。谢谢你!!
这是我的代码 -
class Auth with ChangeNotifier {
final FirebaseAuth _auth = FirebaseAuth.instance;
final GoogleSignIn _googleSignIn = GoogleSignIn();
bool isAuthenticated() {
print('$currentUser inside the isAuthenticated');
if (currentUser == null) {
print('false');
return false;
}
print('true');
return true;
}
Future<FirebaseUser> get currentUser async {
return await _auth.currentUser();
}
Future<FirebaseUser> signInWithEmail(String email, String password) async {
try {
final response = await _auth.signInWithEmailAndPassword(
email: email,
password: password,
);
print(response);
if (response == null) {
print('response is null');
} else {
notifyListeners();
return response.user;
}
} catch (error) {
print('some error');
throw error;
}
}
Future<FirebaseUser> signInWithGoogle() async {
try {
final GoogleSignInAccount _userDetails = await _googleSignIn.signIn();
if (_userDetails == null) {
print('No user found');
} else {
final GoogleSignInAuthentication googleAuth =
await _userDetails.authentication;
final AuthCredential credential = GoogleAuthProvider.getCredential(
accessToken: googleAuth.accessToken,
idToken: googleAuth.idToken,
);
final FirebaseUser user =
(await _auth.signInWithCredential(credential)).user;
return user;
}
notifyListeners();
print('google sign in ran successfully');
} catch (error) {
throw error;
}
}
Future<FirebaseUser> logout() async {
try {
print('logout ran');
print(currentUser); //THIS RETURNS AN INSTANCE OF USER
_auth.signOut().then( (response) {
print('signout successful');
});
await _googleSignIn.signOut();
print(currentUser); //THIS *ALSO* RETURNS AN INSTANCE OF USER
notifyListeners();
return currentUser;
} catch (error) {
print('an error');
}
}
}
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我知道会有一个我无法捕捉到的愚蠢错误,但现在很累!!我已经尝试了可以在 stackoverflow 上找到的其他方法
当您尝试获取当前用户时,未来可能并不完整,您是否尝试过等待而不是注销?
Future<FirebaseUser> logout() async {
try {
print('logout ran');
print(currentUser); //THIS RETURNS AN INSTANCE OF USER
await _auth.signOut();
await _googleSignIn.signOut();
//The problem is with this, you need to await this
//print(currentUser); //THIS *ALSO* RETURNS AN INSTANCE OF USER
var user = await currentUser;
print(user); //prints null
notifyListeners();
return currentUser;
} catch (error) {
print('an error');
}
}
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