Raj*_*h G 5 puppeteer jest-puppeteer
我需要从 span 标签获取文本并验证文本是否等于“check”。
我怎样才能在木偶师中实现这一目标?
下面是我编写的代码示例,如果有人可以帮我解决这个问题,请。
const puppeteer = require("puppeteer");
(async () => {
const browser = await puppeteer.launch({
headless: false,
// "slowMo": 50,
args: ["--start-fullscreen"],
defaultViewport: null,
});
//Page
const page2 = await browser.newPage();
await page2.goto("https://www.flipkart.com");
await page2.waitFor(2000);
await page2.$x("//input[@class='_2zrpKA _1dBPDZ']").then(async (ele) => {
await ele[0].type(username);
});
await page2.waitFor(2000);
await page2.$x("//input[@type='password']").then(async (ele) => {
await ele[0].type(password);
});
await page2.waitFor(2000);
await page2
.$x("//button[@class='_2AkmmA _1LctnI _7UHT_c']")
.then(async (ele) => {
await ele[0].click();
});
await page2.waitFor(2000);
await page2.$x("//input[@class='LM6RPg']").then(async (ele) => {
await ele[0].type("iPhone 11");
});
await page2.waitFor(2000);
await page2.$x("//button[@class='vh79eN']").then(async (ele) => {
await ele[0].click();
});
await page2.waitFor(2000);
await page2.$x("//div[@class='col col-7-12']/div").then(async (ele) => {
await ele[0].click();
});
await page2.waitFor(2000);
let [element] = await page2.$x('//span[@class="_2aK_gu"]');
let text = await page2.evaluate((element) => element.textContent, element);
if (text.includes("Check")) {
console.log("Check Present");
}
if (text.includes("Change")) {
console.log("Change Present");
}
})();
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您可以从所选元素中获取文本,如下所示:
await page.goto(url, {waitUntil: "networkidle2"});
await page.waitForXPath('//span[@class="_2aK_gu"]');
//assuming it's the first element
let [element] = await page.$x('//span[@class="_2aK_gu"]');
let text = await page.evaluate(element => element.textContent, element);
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请注意,page.$x返回一个 ElementHandles 数组,因此此处的代码假设它是第一个元素。我建议您选择比类更具体的 XPath,因为许多元素可能都具有它。
对于条件:
if (text.includes("Check"))
//do this
else if (text.includes("Change"))
//do that
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