cpa*_*age 9 python properties subclass pandas
我试图pd.DataFrame在初始化 (group和timestamp_col)时设置一个具有两个必需参数的子类。我想对这些参数group和运行验证timestamp_col,所以我对每个属性都有一个 setter 方法。这一切都有效,直到我尝试set_index()获得TypeError: 'NoneType' object is not iterable. 似乎没有参数被传递给我的 setter 函数 in test_set_indexand test_assignment_with_indexed_obj。如果我添加if g == None: return到我的 setter 函数中,我可以通过测试用例,但认为这不是正确的解决方案。
我应该如何为这些必需的参数实现属性验证?
下面是我的课:
import pandas as pd
import numpy as np
class HistDollarGains(pd.DataFrame):
@property
def _constructor(self):
return HistDollarGains._internal_ctor
_metadata = ["group", "timestamp_col", "_group", "_timestamp_col"]
@classmethod
def _internal_ctor(cls, *args, **kwargs):
kwargs["group"] = None
kwargs["timestamp_col"] = None
return cls(*args, **kwargs)
def __init__(
self,
data,
group,
timestamp_col,
index=None,
columns=None,
dtype=None,
copy=True,
):
super(HistDollarGains, self).__init__(
data=data, index=index, columns=columns, dtype=dtype, copy=copy
)
self.group = group
self.timestamp_col = timestamp_col
@property
def group(self):
return self._group
@group.setter
def group(self, g):
if g == None:
return
if isinstance(g, str):
group_list = [g]
else:
group_list = g
if not set(group_list).issubset(self.columns):
raise ValueError("Data does not contain " + '[' + ', '.join(group_list) + ']')
self._group = group_list
@property
def timestamp_col(self):
return self._timestamp_col
@timestamp_col.setter
def timestamp_col(self, t):
if t == None:
return
if not t in self.columns:
raise ValueError("Data does not contain " + '[' + t + ']')
self._timestamp_col = t
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这是我的测试用例:
import pytest
import pandas as pd
import numpy as np
from myclass import *
@pytest.fixture(scope="module")
def sample():
samp = pd.DataFrame(
[
{"timestamp": "2020-01-01", "group": "a", "dollar_gains": 100},
{"timestamp": "2020-01-01", "group": "b", "dollar_gains": 100},
{"timestamp": "2020-01-01", "group": "c", "dollar_gains": 110},
{"timestamp": "2020-01-01", "group": "a", "dollar_gains": 110},
{"timestamp": "2020-01-01", "group": "b", "dollar_gains": 90},
{"timestamp": "2020-01-01", "group": "d", "dollar_gains": 100},
]
)
return samp
@pytest.fixture(scope="module")
def sample_obj(sample):
return HistDollarGains(sample, "group", "timestamp")
def test_constructor_without_args(sample):
with pytest.raises(TypeError):
HistDollarGains(sample)
def test_constructor_with_string_group(sample):
hist_dg = HistDollarGains(sample, "group", "timestamp")
assert hist_dg.group == ["group"]
assert hist_dg.timestamp_col == "timestamp"
def test_constructor_with_list_group(sample):
hist_dg = HistDollarGains(sample, ["group", "timestamp"], "timestamp")
def test_constructor_with_invalid_group(sample):
with pytest.raises(ValueError):
HistDollarGains(sample, "invalid_group", np.random.choice(sample.columns))
def test_constructor_with_invalid_timestamp(sample):
with pytest.raises(ValueError):
HistDollarGains(sample, np.random.choice(sample.columns), "invalid_timestamp")
def test_assignment_with_indexed_obj(sample_obj):
b = sample_obj.set_index(sample_obj.group + [sample_obj.timestamp_col])
def test_set_index(sample_obj):
# print(isinstance(a, pd.DataFrame))
assert sample_obj.set_index(sample_obj.group + [sample_obj.timestamp_col]).index.names == ['group', 'timestamp']
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该set_index()方法将在内部调用self.copy()以创建 DataFrame 对象的副本(请参阅此处的源代码),其中它使用您自定义的构造函数方法_internal_ctor()来创建新对象(source)。请注意,self._constructor()与 相同self._internal_ctor(),这是几乎所有 pandas 类的通用内部方法,用于在深度复制或切片等操作期间创建新实例。你的问题实际上源于这个函数:
class HistDollarGains(pd.DataFrame):
...
@classmethod
def _internal_ctor(cls, *args, **kwargs):
kwargs["group"] = None
kwargs["timestamp_col"] = None
return cls(*args, **kwargs) # this is equivalent to calling
# HistDollarGains(data, group=None, timestamp_col=None)
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我猜你是从github 问题复制了这段代码。这些行kwargs["**"] = None明确告诉构造函数设置None为group和timestamp_col。最后,设置器/验证器获取None新值并引发错误。
group因此,您应该为和设置一个可接受的值timestamp_col。
@classmethod
def _internal_ctor(cls, *args, **kwargs):
kwargs["group"] = []
kwargs["timestamp_col"] = 'timestamp' # or whatever name that makes your validator happy
return cls(*args, **kwargs)
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然后您可以删除if g == None: return验证器中的行。
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