是否可以直接从服务层抛出ResponseStatusException,而无需在控制器层面抛出自定义异常和处理?

dev*_*eak 10 java spring exception spring-boot

Spring 5 引入了 ResponseStatusException,直接从服务层抛出这个异常是不是一个好习惯。

情况1:

@Service
public class UserService {
    public User findUserByName(String username) {
       User user = userRepository.findByUsernName(username);
       if(null == user) {
          throw new ResponseStatusException(HttpStatus.NOT_FOUND, "user not found");
       }
    }
}
Run Code Online (Sandbox Code Playgroud)

案例 2: 还是我们需要使用自定义异常并在控制器级别处理它?在这种情况下,我们正在捕获 CustomException 并抛出 ResponseStatusException,为什么我们必须再次捕获自定义异常而不是使用Case 1

@Service
public class UserService {
    public User findUserByName(String username) {
       User user = userRepository.findByUsernName(username);
       if(null == user) {
          throw new UserNotFoundException("user not found");
       }
    }
}

@RestController
public class UserController {

    @GetMapping(path="/get-user")
    public ResponseEntity<User> getUser(String username) {
      try {
         userService.findUserByName(username);
      } catch (UserNotFoundException ex) {
         throw new ResponseStatusException(HttpStatus.NOT_FOUND, "user not found");
      }
    }
}
Run Code Online (Sandbox Code Playgroud)

lcz*_*ski 6

正如评论中提到的,您可以在错误中创建映射。那么你不需要在控制器中使用 try 块。

import org.springframework.http.HttpStatus;
import org.springframework.web.bind.annotation.ResponseStatus;

@ResponseStatus(value = HttpStatus.NOT_FOUND, reason = "user not found")
public class UserNotFoundException extends RuntimeException {

    public UserNotFoundException(String message) {

        super(message);
    }
} 
Run Code Online (Sandbox Code Playgroud)