我有一个非常简单的 json,我试图将其映射到一个对象。
JSON:
[
{
"cust_lpid": "0119b9f7f99ad2161de7b0b",
"cust_uid": "soumavtestflow"
}
]
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我的映射器类:
@JsonIgnoreProperties(ignoreUnknown = true)
public class CustomerSegmentRequest {
@JsonProperty("LPID")
String cust_lpid;
@JsonProperty("UserId")
String cust_uid;
public String getCust_lpid() {
return cust_lpid;
}
public void setCust_lpid(String cust_lpid) {
this.cust_lpid = cust_lpid;
}
public String getCust_uid() {
return cust_uid;
}
public void setCust_uid(String cust_uid) {
this.cust_uid = cust_uid;
}
}
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当我做一个
ObjectMapper objectMapper = new ObjectMapper();
objectMapper.disable(DeserializationFeature.FAIL_ON_UNKNOWN_PROPERTIES);
LPIDCustIDMapper[] custSegResp = objectMapper.readValue(responseBody,CustomerSegmentRequest [].class);
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我没有在 custSegResp 中填充任何值。
但是当我删除它时@JsonProperty它就起作用了。我需要 json 属性名称来映射传入请求,因此不想创建单独的映射类。有没有办法达到同样的目的?
@JsonIgnoreProperties(ignoreUnknown = true)
public class CustomerSegmentRequest {
@JsonAlias({"cust_lpid", "LPID" })
String cust_lpid;
@JsonAlias({"cust_uid", "UserId" })
String cust_uid;
public String getCust_lpid() {
return cust_lpid;
}
public void setCust_lpid(String cust_lpid) {
this.cust_lpid = cust_lpid;
}
public String getCust_uid() {
return cust_uid;
}
public void setCust_uid(String cust_uid) {
this.cust_uid = cust_uid;
}
}
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