我有这段代码:
for i=1:10
v=[2i,i]
@show v
end
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我得到了这个结果:
v = [2, 1]
v = [4, 2]
v = [6, 3]
v = [8, 4]
v = [10, 5]
v = [12, 6]
v = [14, 7]
v = [16, 8]
v = [18, 9]
v = [20, 10]
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现在我想要做的是将所有这些输出收集到一个数组数组中,例如:
[[2,1],[4,2],[6,3]]
而且我真的不知道该怎么做,我尝试了几种无效的解决方案。
小智 5
您可以为此使用数组推导式:
julia> x = [[2i,i] for i in 1:10]
10-element Array{Array{Int64,1},1}:
[2, 1]
[4, 2]
[6, 3]
[8, 4]
[10, 5]
[12, 6]
[14, 7]
[16, 8]
[18, 9]
[20, 10]
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或者使用手动构建一个空的初始数组,并将内部数组一一推入其中的方法:
julia> y = []
0-element Array{Any,1}
julia> for i in 1:10
push!(y,[2i,i])
end
julia> y
10-element Array{Any,1}:
[2, 1]
[4, 2]
[6, 3]
[8, 4]
[10, 5]
[12, 6]
[14, 7]
[16, 8]
[18, 9]
[20, 10]
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