即使它实现了所需的接口,C#泛型方法也会拒绝某个类型

Question

希望我已经正确地描述了它.我有一个'通用方法',如下所示.它接受任何Icomparable/Iequatable类型的列表,并返回下面显示的包含匹配/不匹配项列表的"compareResult"类.

public partial class Comparers
{
    public class compareResult<T>
    {
        public List<T> unchangedItems;
        public List<T> changedItems;
        public List<T> leftOrphans;
        public List<T> rightOrphans;
    }

    public static compareResult<T> stepCompare<T>(List<T> leftList, List<T> rightList, bool confirmUniqueIDs = true) where T : IEquatable<T>, IComparable
    {
        ...

我现在尝试传入一个'LicencedCustomer'列表,该列表定义如下,并实现CompareTo和Equals方法来实现IComparable/IEquatable接口.

public class LicencedCustomer : IEquatable<LicencedCustomer>, IComparable<LicencedCustomer>
    {

        public string LMAA_CODE {get; set;}
    ...

现在我尝试传递以下两个客户列表:

Comparers.compareResult<LicencedCustomer> result = new Comparers.compareResult<LicencedCustomer>();

result = Comparers.stepCompare(leftList, rightList);

但它说"错误1"类型'MFTests.LicencedCustomer'不能在泛型类型或方法'MF.Comparers.stepCompare(System.Collections.Generic.List,System.Collections.Generic.List)中用作类型参数'T'. ,bool)'.没有从'MFTests.LicencedCustomer'到'System.IComparable'的隐式引用转换......

我以为我已经实现了IComparable,虽然它指的是我不太懂的转换.对不起,我做了很长的解释,尽量保持简短.

对我做错了什么的想法？

Answer 1

泛型方法不包括泛型类型标识符T.

where T : IEquatable<T>, IComparable

应该

where T : IEquatable<T>, IComparable<T>