按x排序,然后按y排序

Question

我想对此信息(名称,点和时间)进行排序:

list = [
    {'name':'JOHN', 'points' : 30, 'time' : '0:02:2'},
    {'name':'KARL','points':50,'time': '0:03:00'}
]

所以,我想要的是首先按照分数排序的列表,然后按时间排序(在我的例子中,因为他的时间较少,所以首先是亚马.有任何帮助吗？

我正在尝试这个:

import operator
list.sort(key=operator.itemgetter('points', 'time'))

但得到了一个TypeError: list indices must be integers, not str.

Answer 1

你的例子适合我.我建议你不要list用作变量名,因为它是一个内置类型.

您也可以尝试这样做:

list.sort(key=lambda item: (item['points'], item['time']))

Answer 2

编辑:

示例列表:

>>> a = [
...     {'name':'JOHN', 'points' : 30, 'time' : '0:02:20'},
...     {'name':'LEO', 'points' : 30, 'time': '0:04:20'},
...     {'name':'KARL','points':50,'time': '0:03:00'},
...     {'name':'MARK','points':50,'time': '0:02:00'},
... ]

下降'点':

使用sort()进行就地排序:

>>> a.sort(key=lambda x: (-x['points'],x['time']))
>>> pprint.pprint(a)
[{'name': 'MARK', 'points': 50, 'time': '0:02:00'},
 {'name': 'KARL', 'points': 50, 'time': '0:03:00'},
 {'name': 'JOHN', 'points': 30, 'time': '0:02:20'},
 {'name': 'LEO', 'points': 30, 'time': '0:04:20'}]
>>> 

使用sorted返回排序列表:

>>> pprint.pprint(sorted(a, key=lambda x: (-x['points'],x['time'])))
[{'name': 'MARK', 'points': 50, 'time': '0:02:00'},
 {'name': 'KARL', 'points': 50, 'time': '0:03:00'},
 {'name': 'JOHN', 'points': 30, 'time': '0:02:20'},
 {'name': 'LEO', 'points': 30, 'time': '0:04:20'}]
>>> 

提升'点':

>>> a.sort(key=lambda x: (x['points'],x['time']))
>>> import pprint
>>> pprint.pprint(a)
[{'name': 'JOHN', 'points': 30, 'time': '0:02:20'},
 {'name': 'LEO', 'points': 30, 'time': '0:04:20'},
 {'name': 'MARK', 'points': 50, 'time': '0:02:00'},
 {'name': 'KARL', 'points': 50, 'time': '0:03:00'}]
>>>