Ada*_*one 2 c# stdin stdout minecraft
所以我有一个隐藏的进程(java 命令行应用程序),输出和输入被重定向。我可以很容易地读取输出并且可以正常工作,但是当我发送命令时它不起作用。
我认为我已经确定输入没有被重定向,因为:
(A) 当我发送WriteLine(//command here); Flush没有命令被程序确认时
(B) 当我取消隐藏 cmd 窗口 ( StartInfo.CreateNoWindow = false;) 时,即使 StandardInput 被重定向 ( StartInfo.RedirectStandardInput = true;),我也可以输入命令并运行它们(在 cmd 窗口中)
这是代码:
namespace bukkit
{
public partial class Form1 : Form
{
private static StringBuilder _txt = new StringBuilder();
private static bool _scrolled = false;
Process mncrft = new Process();
public Form1()
{
InitializeComponent();
mncrft.StartInfo.WorkingDirectory = Path.GetTempPath();
mncrft.StartInfo.Arguments = "-Xmx512M -Xms512M -jar C:\\mncrft\\mncrft.jar";
mncrft.StartInfo.FileName = "java.exe";
mncrft.StartInfo.UseShellExecute = false;
mncrft.StartInfo.RedirectStandardOutput = true;
mncrft.StartInfo.RedirectStandardError = true;
mncrft.StartInfo.RedirectStandardInput = true;
mncrft.StartInfo.CreateNoWindow = false;
mncrft.ErrorDataReceived += build_ErrorDataReceived;
//mncrft.OutputDataReceived += build_ErrorDataReceived;
mncrft.EnableRaisingEvents = true;
//mncrft.StandardInput.NewLine = "\r\n";
mncrft.Start();
mncrft.BeginOutputReadLine();
mncrft.BeginErrorReadLine();
}
private void Form1_Load(object sender, EventArgs e)
{
_txt.AppendLine("Starting Minecraft...");
}
private void Form1_Close(object sender, EventArgs e)
{
mncrft.Close();
}
static void build_ErrorDataReceived(object sender, DataReceivedEventArgs e)
{
string msg = e.Data;
if (msg != null && msg.Length > 0)
{
_txt.AppendLine(msg);
_scrolled = false;
}
}
private void mainTimer_Tick(object sender, EventArgs e)
{
if (_txt.Length > 0)
{
txtOutput.Text = _txt.ToString();
// scroll down
if (_scrolled == false)
{
txtOutput.SelectionStart = txtOutput.Text.Length;
txtOutput.ScrollToCaret();
_scrolled = true;
}
}
}
private void Execute_Click(object sender, EventArgs e)
{
if (textBox1.Text.Length > 0)
{
mncrft.StandardInput.WriteLine(textBox1.Text);
mncrft.StandardInput.Flush();
}
}
}
}
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如何重定向输入以便我可以发送命令?
谢谢,亚当
PS:如果这令人困惑,只需发表评论,我会很乐意澄清。
已回答
感谢蒂姆,替换以下几行:
mncrft.StartInfo.FileName = "java.exe";
mncrft.StartInfo.Arguments = "-Xmx512M -Xms512M -jar C:\\mncrft\\mncrft.jar";
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和:
mncrft.StartInfo.FileName = "java";
mncrft.StartInfo.Arguments = "-Xmx512M -Xms512M -jar C:\\mncrft\\bukkit.jar -nojline";
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小智 5
好吧,我整天都在搞这个,我找到了答案。当您使用您的应用程序启动 bukkit 时,您需要将“-nojline”包含到您的流程参数中。这使得 bukkit 的输入与标准输入一起正常工作。
https://github.com/Bukkit/CraftBukkit/commit/22a44d47ac48fb65bb61fb823c84bff9494f5033