创建 Postgres 视图时出现错误：列“id”指定多次

Question

设想：

我有这个 select 语句，将JOIN一堆表放在一起：

SELECT 
    e0.id, e0.name, e0.slug,
    e1.id, e1.edition, e1.url, e1.date, e1.event_id,
    v2.id, v2.title, v2.language, v2.description, v2.provider, v2.videoid, v2.image_url, v2.event_id, v2.edition_id,
    s3.id, s3.name, s3.twitter, s3.website
FROM 
    events AS e0 
LEFT OUTER JOIN 
    editions AS e1 ON e1.event_id = e0.id
LEFT OUTER JOIN 
    videos AS v2 ON v2.edition_id = e1.id
LEFT OUTER JOIN 
    videos_speakers AS v4 ON v4.video_id = v2.id
LEFT OUTER JOIN 
    speakers AS s3 ON v4.speaker_id = s3.id
ORDER BY 
    e1.date DESC;

我想创建一个Postgres View。所以写出来是这样的：

CREATE VIEW all_events 
AS
    SELECT 
        e0.id, e0.name, e0.slug,
        e1.id, e1.edition, e1.url, e1.date, e1.event_id,
        v2.id, v2.title, v2.language, v2.description, v2.provider, v2.videoid, v2.image_url, v2.event_id, v2.edition_id,
        s3.id, s3.name, s3.twitter, s3.website
    FROM 
        events AS e0 
    LEFT OUTER JOIN 
        editions AS e1 ON e1.event_id = e0.id
    LEFT OUTER JOIN 
        videos AS v2 ON v2.edition_id = e1.id
    LEFT OUTER JOIN 
        videos_speakers AS v4 ON v4.video_id = v2.id
    LEFT OUTER JOIN 
        speakers AS s3 ON v4.speaker_id = s3.id
    ORDER BY 
        e1.date DESC;

我不断收到此错误：

错误：多次指定列“id”

问题：

1. 我该如何修复这个错误？我想创建一个名为“all_events”的视图。
2. Postgres View是否类似于其他语言中的别名？

Postgres 新手，正在阅读文档，但试图理解这里的心理模型。

Answer 1

您有多个相同的列名称。即使您选择的e0.id列仍然是 name (only) id。

但在视图（或表）范围内，每个列名必须是唯一的。

您需要为每个重复列提供别名：

CREATE VIEW all_events AS
SELECT  e0.id as event_id, --<< here 
        e0.name as event_name, --<< here 
        e0.slug,
        e1.id as edition_id,  --<< here
        e1.edition, 
        e1.url, 
        e1.date, 
        e1.event_id as edition_event_id, --<< here
        v2.id as video_id,  --<< here
        v2.title, 
        v2.language, 
        v2.description, 
        v2.provider, 
        v2.videoid, 
        v2.image_url, 
        v2.event_id as video_event_id, --<< here 
        v2.edition_id as video_edition_id, --<< here
        s3.id as speaker_id,  --<< here
        s3.name as speaker_name, --<< here 
        s3.twitter, 
        s3.website
FROM events AS e0 
  LEFT OUTER JOIN editions AS e1 ON e1.event_id = e0.id
  LEFT OUTER JOIN videos AS v2 ON v2.edition_id = e1.id
  LEFT OUTER JOIN videos_speakers AS v4 ON v4.video_id = v2.id
  LEFT OUTER JOIN speakers AS s3 ON v4.speaker_id = s3.id;

尽管 Postgres 允许这样做，但我强烈建议不要使用语句创建视图ORDER BY。如果您按不同的列对该视图的结果进行排序，Postgres 将对数据进行两次排序。