我有一个包含多个列的数据框,其中包含我想要unnest(或unchop)的列表列。但是,它们的长度不同,因此产生的错误是Error: No common size for...
这是一个 reprex 来显示哪些有效,哪些无效。
library(tidyr)
library(vctrs)
# This works as expected
df_A <- tibble(
ID = 1:3,
A = as_list_of(list(c(9, 8, 5), c(7,6), c(6, 9)))
)
unchop(df_A, cols = c(A))
# A tibble: 7 x 2
ID A
<int> <dbl>
1 1 9
2 1 8
3 1 5
4 2 7
5 2 6
6 3 6
7 3 9
# This works as expected as the lists are the same lengths
df_AB_1 <- tibble(
ID = 1:3,
A = as_list_of(list(c(9, 8, 5), c(7,6), c(6, 9))),
B = as_list_of(list(c(1, 2, 3), c(4, 5), c(7, 8)))
)
unchop(df_AB_1, cols = c(A, B))
# A tibble: 7 x 3
ID A B
<int> <dbl> <dbl>
1 1 9 1
2 1 8 2
3 1 5 3
4 2 7 4
5 2 6 5
6 3 6 7
7 3 9 8
# This does NOT work as the lists are different lengths
df_AB_2 <- tibble(
ID = 1:3,
A = as_list_of(list(c(9, 8, 5), c(7,6), c(6, 9))),
B = as_list_of(list(c(1, 2), c(4, 5, 6), c(7, 8, 9, 0)))
)
unchop(df_AB_2, cols = c(A, B))
# Error: No common size for `A`, size 3, and `B`, size 2.
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我想为df_AB_2上面实现的输出如下,其中每个列表都未切碎,缺失值用 NA 填充:
# A tibble: 10 x 3
ID A B
<dbl> <dbl> <dbl>
1 1 9 1
2 1 8 2
3 1 5 NA
4 2 7 4
5 2 6 5
6 2 NA 6
7 3 6 7
8 3 9 8
9 3 NA 9
10 3 NA 0
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我已经提到这个问题,在Github和StackOverflow上这里。
任何想法如何实现上述结果?
> packageVersion("tidyr")
[1] ‘1.0.0’
> packageVersion("vctrs")
[1] ‘0.2.0.9001’
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这是通过 dplyr 的一个想法,您可以根据需要将其推广到任意数量的列,
library(tidyverse)
df_AB_2 %>%
pivot_longer(c(A, B)) %>%
mutate(value = lapply(value, `length<-`, max(lengths(value)))) %>%
pivot_wider(names_from = name, values_from = value) %>%
unnest() %>%
filter(rowSums(is.na(.[-1])) != 2)
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这使,
Run Code Online (Sandbox Code Playgroud)# A tibble: 10 x 3 ID A B <int> <dbl> <dbl> 1 1 9 1 2 1 8 2 3 1 5 NA 4 2 7 4 5 2 6 5 6 2 NA 6 7 3 6 7 8 3 9 8 9 3 NA 9 10 3 NA 0
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