在 GitHub 操作中从节点程序运行 Powershell 脚本

Question

嗯，是的，这是一回事。在尝试直接运行 PS 脚本并失败后，让我们尝试从节点脚本运行它的迂回方式，这在 GitHub 操作环境中是合法的。所以经过多次尝试，这是我的最后一个（取自这个答案：

var spawn = require("child_process").spawn,child;
var workspace = process.env.GITHUB_WORKSPACE;
var file = workspace + "\\upgrade.ps1";
console.log( "Workspace ", workspace,  " file ", file );
child = spawn("powershell.exe",[ file ]); // more stuff to print output after this

这失败了：

Workspace  d:\a\rakudo-star-fix-action\rakudo-star-fix-action  file  d:\a\rakudo-star-fix-action\rakudo-star-fix-action\upgrade.ps1
Powershell Errors: d:\a\rakudo-star-fix-action\rakudo-star-fix-action\upgrade.ps1 : The term 

Powershell Errors: 'd:\a\rakudo-star-fix-action\rakudo-star-fix-action\upgrade.ps1' is not recognized as the name of a cmdlet, function, 
script file, or operable program. Check the spelling of the name, or if a path was included, verify that the path is 
correct and try again.
At line:1 char:1
+ d:\a\rakudo-star-fix-action\rakudo-star-fix-action\upgrade.ps1
+ ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
    + CategoryInfo          : ObjectNotFound: (d:\a\rakudo-sta...ion\upgrade.ps1:String) [], CommandNotFoundException
    + FullyQualifiedErrorId : CommandNotFoundException


Powershell Script finished

我真的不知道这里发生了什么。node脚本和PS脚本在同一个目录下，是仓库的根目录，在那个环境变量下应该是可用的。

Answer 1

工作区实际上与您的文件在您的存储库中的位置不同。

在 nodejs 中，您可以编写以下内容来获取当前工作目录及其文件：

const directoryPath = __dirname;
console.log(directoryPath);
fs.readdir(directoryPath, function(err, files) {
  if (err) {
    console.log("Error getting directory information.")
    console.log(err)
  } else {
    files.forEach(function(file) {
      console.log(file)
    })
  }
})

然后，您可以指定一个 const 变量const directoryPath = __dirname;，然后将其连接到您的var file：

const directoryPath = __dirname;
var spawn = require("child_process").spawn,child;
var file = directoryPath + "\\upgrade.ps1";
child = spawn("powershell.exe",["-NoProfile", "-File", file ])

powershell 脚本应该从那里运行。

编辑：

我刚刚在此处的测试仓库中对此进行了测试