Sim*_*ine 7 haskell overloaded-lists
我有一个用于重构练习的测试套件,我希望它与Data.List
和Data.List.NonEmpty
. 练习由一个函数组成,foo :: [Foo] -> Foo
测试套件有一些
data Case = Case
{ description :: String
, input :: [Foo]
, expected :: Foo
}
cases :: [Case]
cases =
[ Case { description = "blah blah"
, input = [Foo 1, Foo 2, Foo 3]
, expected = Foo 1
}
, ...
]
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为了使测试套件多态OverloadedLists
,我试过
{-# LANGUAGE OverloadedLists #-}
...
data Case list = Case
{ description :: String
, input :: list Foo
, expected :: Foo
}
cases =
[ Case { description = "blah blah"
, input = [Foo 1, Foo 2, Foo 3]
, expected = Foo 1
}
, ...
]
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但这给了我错误
• Couldn't match expected type ‘GHC.Exts.Item (list0 Foo)’
with actual type ‘Foo’
The type variable ‘list0’ is ambiguous
...
|
50 | , input = [Foo 1, Foo 2, Foo 3]
| ^^^^^
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我想将IsList list
约束移动到Case
数据类型,就像这样
• Couldn't match expected type ‘GHC.Exts.Item (list0 Foo)’
with actual type ‘Foo’
The type variable ‘list0’ is ambiguous
...
|
50 | , input = [Foo 1, Foo 2, Foo 3]
| ^^^^^
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但这给了我错误
• Expected kind ‘* -> *’, but ‘list’ has kind ‘*’
• In the type ‘list Foo’
In the definition of data constructor ‘Case’
In the data declaration for ‘Case’
|
24 | Case :: IsList list => String -> list Foo -> Foo -> Case list
| ^^^^^^^^
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我不确定这里最简单的方法是什么。任何提示?
这不起作用的原因是因为 a 的Item
类型本身List (l Foo) => l
不是。该扩展对其进行了抽象,因此它期望您的列表文字的元素为 type 。 Foo
Item (l Foo)
但是,您可以添加一个类型约束,表明这些项目确实是 type Foo
:
{-# LANGUAGE OverloadedLists #-}
data Case list = Case
{ description :: String
, input :: list Foo
, expected :: Foo
}
cases :: (IsList (l Foo), Item (l Foo) ~ Foo) => [Case l]
cases = [
Case { description = "blah blah"
, input = [Foo 1, Foo 2, Foo 3]
, expected = Foo 1
}
]
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因此,我们在这里说Item (l Foo)
应该与 相同Foo
。
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