我的if语句在我的while循环中的每个if语句上打印，无论它是否为false

Question

所以我正在做一个文字冒险游戏，我只是编程指导。我有一个带有南北等的脚本，然后是一条if语句，该语句表明如果用户输入的不是方向，它会说这不是方向，并循环到顶部，但不起作用。即使我输入正确的输入，也将始终打印那不是方向。有人可以帮忙吗？

#include <iomanip>
#include <string>
#include <iostream>
using namespace std;



int main()
{
    string input;
    while (input != "north", "n", "south", "s", "east", "e") {
        cout << "Enter a direction" << endl;
        getline(cin, input);
        if (input == "north" || input == "n") {
            cout << "north" << endl;
        }
        if (input == "west" || input == "w") {
            cout << "west" << endl;
        }
        if (input == "east" || input == "e") {
            cout << "east" << endl;
        }
        if (input == "south" || input == "s") {
            cout << "south" << endl;
        }
        if (input != "n", "s", "e", "w")
        {
            cout << "That is not a direction" << endl;
        }
    }
    return 0;
}

Answer 1

正如我在评论中所说：

在C ++中，"north", "n", "south", "s", "east", "e"将始终评估为"e"和"n", "s", "e", "w"将始终评估为"w"

对于所有可能的情况，进行此比较的正确方法是：

 while (input != "north" && input != "n" && input != "south" && input != "s" && input != "east" && input != "e" && input != "west" && input != "w") {...}

对于如果是：

if (input != "n" || input != "s" || input != "e" || input != "w") {...}

演示版