我有一种情况,我需要使用密钥拆分后端给定的Json对象。这是后端提供的JSON的示例。
{
"answer": {
"E2": "Tony Stark",
"E3": "1",
"E4": "2",
"E6": "4",
"E8": "9120",
"E9": "01",
"F1": "Marvel",
"F2": "1",
"F4": "2",
"F6": "4",
"F8": "9120",
"F9": "01",
"G1": "02",
"G2": "02",
"G3": "02",
"H10": "Car"
}
}
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我可以将答案分为E,F,G和H部分吗?预期结果是
{
"answer": [
{
"E2": "Tony Stark",
"E3": "1",
"E4": "2",
"E6": "4",
"E8": "9120",
"E9": "01",
"sectionName": "E"
},
{
"F1": "Marvel",
"F2": "1",
"F4": "2",
"F6": "4",
"F8": "9120",
"F9": "01",
"sectionName": "F"
},
{
"G1": "02",
"G2": "02",
"G3": "02",
"sectionName": "G"
},
{
"H10": "Car",
"sectionName": "H"
}
]
}
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那里一定有一个天才可以解决我的问题。非常感谢。任何建议表示赞赏。
遍历entries对象的,并根据键的第一个字母将它们分组。如果组对象alrady以字母作为键,请对其进行更新。否则,将字母作为键添加到组对象。用于在输出中Object.values()获取answer所需的数组
const input={answer:{E2:"Tony Stark",E3:"1",E4:"2",E6:"4",E8:"9120",E9:"01",F1:"Marvel",F2:"1",F4:"2",F6:"4",F8:"9120",F9:"01",G1:"02",G2:"02",G3:"02",H10:"Car"}};
const group = {};
for (const [k, v] of Object.entries(input.answer)) {
const sectionName = k.charAt(0);
if (group[sectionName])
group[sectionName][k] = v;
else
group[sectionName] = { sectionName, [k]: v };
}
const answer = Object.values(group)
console.log({ answer })Run Code Online (Sandbox Code Playgroud)
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