Luk*_*sen 11 python type-hinting mypy python-typing
我想声明一个带有抽象方法的基类,该方法具有类型化参数,以便实现类可以为该参数指定更具体的类型,例如:
from abc import ABC, abstractmethod
class Job(ABC):
pass
class EasyJob(Job):
pass
class HardJob(Job):
pass
class Worker(ABC):
@abstractmethod
def run(self, job: Job) -> None:
raise NotImplementedError()
class EasyWorker(Worker):
def run(self, job: EasyJob) -> None:
pass
class HardWorker(Worker):
def run(self, job: HardJob) -> None:
pass
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然而,mypy 对此抱怨是可以理解的:
line 14: error: Argument 1 of "run" is incompatible with supertype "Worker"; supertype defines the argument type as "Job"
line 18: error: Argument 1 of "run" is incompatible with supertype "Worker"; supertype defines the argument type as "Job"
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Python中有什么方法可以促进这种结构吗?
小智 10
您可能想要Bounded Parametric Polymorphism。另请参阅有关有界类型变量的这一部分。
在Worker 中,您想说您的方法run是泛型的,因为它采用某种未指定类型T的值,而T是Job的子类型。从Worker派生的类然后将T替换为具体类型:
from abc import ABC, abstractmethod
from typing import Generic, TypeVar
class Job(ABC):
pass
class EasyJob(Job):
pass
class HardJob(Job):
pass
T = TypeVar('T', bound=Job)
class Worker(ABC, Generic[T]):
@abstractmethod
def run(self, job: T) -> None:
raise NotImplementedError()
class EasyWorker(Worker[EasyJob]):
def run(self, job: EasyJob) -> None:
pass
class HardWorker(Worker[HardJob]):
def run(self, job: HardJob) -> None:
pass
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