gue*_*gui 3 ruby ruby-on-rails graphql
我正在使用 app为我的graphql-ruby编写一个基于devise- jwt的身份验证系统。在这个过程中,我为创建一个新的用户帐户做了一个改变,它需要 7 个参数,这在我的代码中产生了很多重复:
module Mutations
class SignUpMutation < Mutations::BaseMutation
argument :email, String, required: true
argument :password, String, required: true
argument :family_name, String, required: true
argument :family_name_phonetic, String, required: true
argument :given_name, String, required: true
argument :given_name_phonetic, String, required: true
argument :newsletter_optin, Boolean, required: false
field :token, String, null: true
field :user, Types::UserType, null: true
def resolve(email:, password:,
family_name:, family_name_phonetic:,
given_name:, given_name_phonetic:,
newsletter_optin:
)
result = {
token: nil,
user: nil
}
new_user = User.new(
email: email,
password: password,
family_name: family_name,
family_name_phonetic: family_name_phonetic,
given_name: given_name,
given_name_phonetic: given_name_phonetic,
newsletter_optin: newsletter_optin
)
if new_user.save!
result[:token] = new_user.token
result[:user] = new_user
end
result
end
end
end
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我怎么能干掉这个以避免在所有地方重复突变参数的名称?
先感谢您!
回答我自己的问题。不必处理这么多参数的正确方法是使用输入对象而不是单独的参数。来自graphql-ruby 文档:
输入对象类型是 GraphQL 操作的复杂输入。它们非常适合需要大量结构化输入的字段,例如突变或搜索字段。
所以我已经定义了我的输入对象:
module Types
class UserAttributes < Types::BaseInputObject
description 'Attributes for creating or updating a user'
argument :email, String, required: true
argument :password, String, required: true
argument :family_name, String, required: true
argument :family_name_phonetic, String, required: true
argument :given_name, String, required: true
argument :given_name_phonetic, String, required: true
argument :newsletter_optin, Boolean, required: false
end
end
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然后像这样重构我的突变:
module Mutations
class SignUpMutation < Mutations::BaseMutation
argument :attributes, Types::UserAttributes, required: true
field :token, String, null: true
field :user, Types::UserType, null: true
def resolve(attributes:)
result = {
token: nil,
user: nil
}
new_user = User.new(attributes.to_hash)
if new_user.save!
result[:token] = new_user.token
result[:user] = new_user
end
result
end
end
end
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最后,这段代码感觉更像 ruby :)
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