指定的输入之一无效

Mat*_*t M 4 azure-cosmosdb

使用 nuget 包“Microsoft.Azure.Cosmos”(版本 3.4.1)我无法对非常基本的模型(三个属性)执行 upsert 操作。我查看了宇宙样本并将它们用作起点,但无法弄清楚我做错了什么

当尝试执行以下代码时,我收到以下错误 “指定的输入之一无效”

完整代码

public class CatalogModel
{
    [JsonProperty("id")]
    public long Id { get { return ModelId; } }

    [JsonProperty("ModelId")]
    public long ModelId { get; set; }

    public string Name { get; set; }
}

public async Task Do(CatalogModel model)
{
    string databaseId = "<dbid_here>"; // in real application this will not be hard coded
    string containerId = "<containerid_here>"; // in real application this will not be hard coded
    Database database = await _client.CreateDatabaseIfNotExistsAsync(databaseId);

    // Delete the existing container to prevent create item conflicts
    using (await database.GetContainer(containerId).DeleteContainerStreamAsync())
    { }

    // We create a partitioned collection here which needs a partition key. Partitioned collections
    // can be created with very high values of provisioned throughput (up to Throughput = 250,000)
    // and used to store up to 250 GB of data. You can also skip specifying a partition key to create
    // single partition collections that store up to 10 GB of data.
    ContainerProperties containerProperties = new ContainerProperties(containerId, partitionKeyPath: "/ModelId");

    // Create with a throughput of 1000 RU/s
    Container _container = await database.CreateContainerIfNotExistsAsync(
            containerProperties,
            throughput: 1000);

    try
    {
        var id = model.ModelId.ToString();
        var partitionKey = new PartitionKey(id);


        var response = await _container.ReadItemStreamAsync(
            id: id,
            partitionKey: partitionKey,
            cancellationToken: context.CancellationToken);

        ItemResponse<CatalogModel> itemResponse;
        if (response.IsSuccessStatusCode)
        {
            //TODO: implement
        }
        else
        {
            var item = model
            // This is not working either
            //itemResponse = await _container.UpsertItemAsync<CatalogModel>(
            //    item,
            //    partitionKey: partitionKey,
            //    cancellationToken: context.CancellationToken);
            using (Stream stream = ToStream<CatalogModel>(item))
            {
                string body;
                using (var reader = new StreamReader(stream, new UTF8Encoding(false, true), false, 1024, true))
                {
                    body = await reader.ReadToEndAsync();
                }
                stream.Seek(0, SeekOrigin.Begin);
                using (ResponseMessage responseMessage = await _container.UpsertItemStreamAsync(
                    partitionKey: partitionKey,
                    streamPayload: stream))
                {
                    using (var reader = new StreamReader(responseMessage.Content, new UTF8Encoding(false, true), false, 1024, true))
                    {
                        body = await reader.ReadToEndAsync();
                    }
                }
            }

        }
    }
    catch (Exception ex)
    {

        throw;
    }
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调试信息

Mat*_*nta 5

id需要是一个string. 您的模型可能需要是:

public class CatalogModel
{
    [JsonProperty("id")]
    public string Id { get { return ModelId.ToString(); } }

    [JsonProperty("ModelId")]
    public long ModelId { get; set; }

    public string Name { get; set; }
}
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Ton*_* Ju 5

有两个步骤可以让您的代码正常工作。

  1. id需要是一个string. 您可以将代码更改为@Matias Quaranta 的答案。

  2. 传递正确的partitionKey。正如您定义为long类型,但您传递了一个字符串值。

使用var partitionKey = new PartitionKey(model.ModelId);而不是 varpartitionKey = new PartitionKey(id);

Step2 将解决如下问题。

在此输入图像描述


Ati*_*ifm 5

有同样的问题。看起来Id可以是其他类型,我自己使用一个guid。我有一个记录看起来像

  public record Data(Guid Id, string Field1);
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在 C# 中,命名标准有点强制名称与 CosmosDB 期望的不匹配。你确实有能力更改命名策略,使其更好地与 C# 标准一起工作...实际上,这应该是默认值

var client = new CosmosClient(
    connectionString, 
    new CosmosClientOptions 
    { 
        SerializerOptions = new CosmosSerializationOptions { PropertyNamingPolicy = CosmosPropertyNamingPolicy.CamelCase },
    });
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现在,您的字段“Id”已映射到“id”,并且错误消失了。