当对象值是带有jQuery的对象数组时,遍历JSON

tom*_*ber 1 javascript jquery json

这是我的外部JSON:

{"meta": {"limit": 20, "next": null, "offset": 0, "previous": null, "total_count": 3}, "objects": [{"body": "this is copy text", "id": "1", "pub_date": "2011-05-04T12:23:26", "resource_uri": "/api/v1/entry/1/", "slug": "test-title-number-one", "title": "test title number one", "user": "/api/v1/user/1/"}, {"body": "this is the second test text", "id": "2", "pub_date": "2011-05-04T15:01:16", "resource_uri": "/api/v1/entry/2/", "slug": "second-test", "title": "Second test", "user": "/api/v1/user/1/"}, {"body": "item three", "id": "3", "pub_date": "2011-05-05T12:04:04", "resource_uri": "/api/v1/entry/3/", "slug": "item-3", "title": "item 3", "user": "/api/v1/user/1/"}]}
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这是我的JS:

$.ajax({url: "/api/v1/entry/?format=json", 
dataType: "json",
success: function(json) {
    $.each(json.objects[0], function(key, value) { 
      alert(key + ': ' + value); 
    });
}
});
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我可以用$ .each(json.objects [0] ...)索引数组中的对象,但我需要能够命中数组中的每个对象,我不知道为什么只需$ .each(json.对象...不起作用.谢谢!

Cha*_*had 6

只需做一个普通的JS循环:

for(var i = 0; i < json.objects.length; ++i)
{
   $.each(json.objects[i], function(key, value) { 
      alert(key + ': ' + value); 
    });
}
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