如何在Java中初始化对象数组

Joh*_*ams 71 java arrays initialization object

我想为BlackJack游戏初始化一个Player对象数组.我已经阅读了很多关于初始化原始对象的各种方法,比如一个int数组或一个字符串数组但是我不能把这个概念带到我想要做的事情(见下文).我想返回一个初始化的Player对象数组.要创建的播放器对象的数量是一个整数,我会提示用户.我在想,构造函数可以接受一个整数值,并在初始化Player对象的某些成员变量时相应地命名播放器.我觉得我很亲密,但仍然很困惑.

static class Player
{
    private String Name;
    private int handValue;
    private boolean BlackJack;
    private TheCard[] Hand;

    public Player(int i)
    {
        if (i == 0)
        {
            this.Name = "Dealer"; 
        }
        else
        {
            this.Name = "Player_" + String.valueOf(i);
        }
        this.handValue = 0;
        this.BlackJack = false;
        this.Hand = new TheCard[2];
    } 
}
private static Player[] InitializePlayers(int PlayerCount)
{ //The line below never completes after applying the suggested change
    Player[PlayerCount] thePlayers;
    for(int i = 0; i < PlayerCount + 1; i++)
    {
        thePlayers[i] = new Player(i);
    }
    return thePlayers;
}
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编辑 - 更新: 这是我改变这一点后得到的,因为我理解你的建议:

Thread [main] (Suspended)   
    ClassNotFoundException(Throwable).<init>(String, Throwable) line: 217   
    ClassNotFoundException(Exception).<init>(String, Throwable) line: not available 
    ClassNotFoundException.<init>(String) line: not available   
    URLClassLoader$1.run() line: not available  
    AccessController.doPrivileged(PrivilegedExceptionAction<T>, AccessControlContext) line: not available [native method]   
    Launcher$ExtClassLoader(URLClassLoader).findClass(String) line: not available   
    Launcher$ExtClassLoader.findClass(String) line: not available   
    Launcher$ExtClassLoader(ClassLoader).loadClass(String, boolean) line: not available 
    Launcher$AppClassLoader(ClassLoader).loadClass(String, boolean) line: not available 
    Launcher$AppClassLoader.loadClass(String, boolean) line: not available  
    Launcher$AppClassLoader(ClassLoader).loadClass(String) line: not available  
    BlackJackCardGame.InitializePlayers(int) line: 30   
    BlackJackCardGame.main(String[]) line: 249  
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Boz*_*zho 91

几乎没问题.只要:

Player[] thePlayers = new Player[playerCount + 1];
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让循环为:

for(int i = 0; i < thePlayers.length; i++)
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请注意,java约定规定方法和变量的名称应以小写字母开头.

更新:将您的方法放在类体中.


Bal*_*a R 21

代替

Player[PlayerCount] thePlayers;
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你要

Player[] thePlayers = new Player[PlayerCount];
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for(int i = 0; i < PlayerCount ; i++)
{
    thePlayers[i] = new Player(i);
}
return thePlayers;
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应返回使用Player实例初始化的数组.

编辑:

在维基百科上查看此表,了解广泛使用的java的命名约定.


Ugu*_*mru 14

如果您不确定数组的大小或是否可以更改,则可以执行此操作以获得静态数组.

ArrayList<Player> thePlayersList = new ArrayList<Player>(); 

thePlayersList.add(new Player(1));
thePlayersList.add(new Player(2));
.
.
//Some code here that changes the number of players e.g

Players[] thePlayers = thePlayersList.toArray();
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  • @Deqing在这种情况下,我更喜欢`Object thePlayersList = new ArrayList <Player>();`. (2认同)

Joh*_*kel 11

If you can hard-code the number of players

Player[] thePlayers = {
    new Player(0),
    new Player(1),
    new Player(2),
    new Player(3)
};
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