Jef*_*eff 4 python subplot plotly
鉴于我有来自此链接的以下代码:
from plotly.subplots import make_subplots
import plotly.graph_objects as go
fig = make_subplots(rows=1, cols=2)
fig.add_trace(
go.Scatter(x=[1, 2, 3], y=[4, 5, 6]),
row=1, col=1
)
fig.add_trace(
go.Scatter(x=[20, 30, 40], y=[50, 60, 70]),
row=1, col=2
)
fig.update_layout(height=600, width=800, title_text="Subplots")
fig.show()
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这段代码的问题是,xaxis
和yaxis
没有任何标签。除此之外,当前代码仅对所有图应用一个标题,但是我想对每个散点图应用不同的标题。
我怎样才能做到这一点?
ves*_*and 11
此代码中的问题是,xaxis 和 yaxis 没有任何标签。
您可以通过设置图形结构的子集来编辑任何轴:
fig['layout']['xaxis']['title']='Label x-axis 1'
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除此之外,当前代码仅将一个标题应用于所有地块
根据用户 shaik moeed 提到的情节版本,您可以subplot_titles
在图形定义中包含:
fig = make_subplots(rows=1, cols=2, subplot_titles=('Subplot title1', 'Subplot title2'))
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阴谋:
代码:
from plotly.subplots import make_subplots
import plotly.graph_objects as go
# plotly fig setup
fig = make_subplots(rows=1,
cols=2,
subplot_titles=('Subplot title1', 'Subplot title2'))
# traces
fig.add_trace(
go.Scatter(x=[1, 2, 3], y=[4, 5, 6]),
row=1, col=1
)
fig.add_trace(
go.Scatter(x=[20, 30, 40], y=[50, 60, 70]),
row=1, col=2
)
# edit axis labels
fig['layout']['xaxis']['title']='Label x-axis 1'
fig['layout']['xaxis2']['title']='Label x-axis 2'
fig['layout']['yaxis']['title']='Label y-axis 1'
fig['layout']['yaxis2']['title']='Label y-axis 2'
# plot it
fig.show()
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sha*_*eed 10
从 Plotly 4.0.0 开始,您可以将主轴标题分别添加为 x_title 和 y_title:
from plotly.subplots import make_subplots
fig = make_subplots(rows=2,
cols=2,
x_title='Your master x-title',
y_title='Your master y-title',
subplot_titles=('Subplot title1', 'Subplot title2',
'Subplot title3', 'Subplot title4'))
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示例代码:
from plotly.subplots import make_subplots
import plotly.graph_objects as go
fig = make_subplots(rows=1,
cols=2,
x_title='Your master x-title',
y_title='Your master y-title',
subplot_titles=('Subplot title1', 'Subplot title2'))
fig.add_trace(
go.Scatter(x=[1, 2, 3], y=[4, 5, 6]),
row=1, col=1
)
fig.add_trace(
go.Scatter(x=[20, 30, 40], y=[50, 60, 70]),
row=1, col=2
)
fig.update_layout(title_text="Side By Side Subplots with diffrent sub titles")
fig.show()
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