在一个软件中,我将两个数组合并为array_merge函数.但我需要将相同的数组(当然具有相同的键)添加到现有数组中.
问题:
$A = array('a' => 1, 'b' => 2, 'c' => 3);
$B = array('c' => 4, 'd'=> 5);
array_merge($A, $B);
// result
[a] => 1 [b] => 2 [c] => 4 [d] => 5
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如你所见,'c' => 3错过了.
那么我怎么能用相同的键合并所有这些呢?
Jon*_*Jon 51
你需要使用array_merge_recursive而不是array_merge.当然,'c'在数组中只能有一个键等于,但关联的值将是包含3和的两个数组4.
diE*_*cho 23
$A = array('a' => 1, 'b' => 2, 'c' => 3);
$B = array('c' => 4, 'd'=> 5);
$c = array_merge_recursive($A,$B);
echo "<pre>";
print_r($c);
echo "</pre>";
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将返回
Array
(
[a] => 1
[b] => 2
[c] => Array
(
[0] => 3
[1] => 4
)
[d] => 5
)
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小智 6
$arr1 = array(
"0" => array("fid" => 1, "tid" => 1, "name" => "Melon"),
"1" => array("fid" => 1, "tid" => 4, "name" => "Tansuozhe"),
"2" => array("fid" => 1, "tid" => 6, "name" => "Chao"),
"3" => array("fid" => 1, "tid" => 7, "name" => "Xi"),
"4" => array("fid" => 2, "tid" => 9, "name" => "Xigua")
);
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如果你想转换这个数组如下:
$arr2 = array(
"0" => array(
"0" => array("fid" => 1, "tid" => 1, "name" => "Melon"),
"1" => array("fid" => 1, "tid" => 4, "name" => "Tansuozhe"),
"2" => array("fid" => 1, "tid" => 6, "name" => "Chao"),
"3" => array("fid" => 1, "tid" => 7, "name" => "Xi")
),
"1" => array(
"0" =>array("fid" => 2, "tid" => 9, "name" => "Xigua")
)
);
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所以,我的回答是这样的:
$outer_array = array();
$unique_array = array();
foreach($arr1 as $key => $value)
{
$inner_array = array();
$fid_value = $value['fid'];
if(!in_array($value['fid'], $unique_array))
{
array_push($unique_array, $fid_value);
unset($value['fid']);
array_push($inner_array, $value);
$outer_array[$fid_value] = $inner_array;
}else{
unset($value['fid']);
array_push($outer_array[$fid_value], $value);
}
}
var_dump(array_values($outer_array));
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希望这个答案会在某个时候对某人有所帮助。