Abh*_* B. 43 jquery jquery-ui javascript-framework jquery-selectors
我有字符串数组
"美国","加拿大","阿根廷","亚美尼亚","阿鲁巴","澳大利亚","奥地利","阿塞拜疆","巴哈马","孟加拉国","白俄罗斯","比利时"**,......等
我想从字符串数组创建一个动态列表,如下所示: -
<ul class="mylist" style="z-index: 1; top: 474px; left: 228px; display: none; width: 324px;" >
<li class="ui-menu-item" role="menuitem">
<a class="ui-all" tabindex="-1">
United States
</a>
</li>
<li class="ui-menu-item" role="menuitem">
<a class="ui-all" tabindex="-1">
Canada
</a>
</li>
<li> .... </li>
.....
</ul>
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如何使用jQuery?
Sai*_*kar 86
var countries = ['United States', 'Canada', 'Argentina', 'Armenia'];
var cList = $('ul.mylist')
$.each(countries, function(i)
{
var li = $('<li/>')
.addClass('ui-menu-item')
.attr('role', 'menuitem')
.appendTo(cList);
var aaa = $('<a/>')
.addClass('ui-all')
.text(countries[i])
.appendTo(li);
});
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SM *_*Ali 13
使用数组的连接方法更好的方法
var countries = ['United States', 'Canada', 'Argentina', 'Armenia'];
var list = '<ul class="myList"><li class="ui-menu-item" role="menuitem"><a class="ui-all" tabindex="-1">' + countries.join('</a></li><li>') + '</li></ul>';
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tok*_*and 10
使用ES6,您可以编写此内容(跳过一些HTML属性以避免不必要的噪音):
const countries = ['United States', 'Canada', 'Argentina', 'Armenia'];
const $ul = $('<ul>', {class: "mylist"}).append(
countries.map(country =>
$("<li>").append($("<a>").text(country))
)
);
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var countries = ['United States', 'Canada', 'Argentina', 'Armenia'];
var cList = $('ul.mylist')
$.each(countries, function(i) {
var li = $('<li/>')
.addClass('ui-menu-item')
.attr('role', 'menuitem')
.appendTo(cList);
var a = $('<a/>')
.addClass('ui-all')
.text( this )
.appendTo(li);
});
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