Python Post 请求到 API

che*_*noi 2 python api json python-requests

这可能是一个简单的问题,但我找不到为什么我无法将 post 请求调用到 api url 的问题。我对类似的问题进行了交叉检查,但我的仍然有问题。

这是脚本

import requests
import json

#API details
url = "http://192.168.1.100:9792/api/scan"
body = {"service":"scan", "user_id":"1", "action":"read_all", "code":"0"}
headers = {'Content-Type': 'application/json'}

#Making http post request
response = requests.post(url, headers=headers, data=body, verify=False)
print(response)

#Decode response.json() method to a python dictionary for data process utilization
dictData = response.json()
print(dictData)

with open('scan.json', 'w') as fp:
  json.dump(dictData, fp, indent=4, sort_keys=True)
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获取错误

 raise ValueError("No JSON object could be decoded")
ValueError: No JSON object could be decoded
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打印(响应)得到回报

<Response [200]>
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如果我像下面一样运行 curl ,那么它会从 api post 请求返回数据

curl --header "Content-Type: application/json" --request POST --data '{"service":"scan","user_id":"1","action":"read_all","code":"0"}' http://192.168.1.100:9792/api/scan

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使用 curl 好的......但是当我使用 requests/json python 有问题......我想我可能会错过一些我无法检测到的东西。请帮助并指出我正确的方法。谢谢你。

Pra*_*iel 5

我有类似的错误,转储我的数据解决了这个问题。尝试将您的身体作为转储传递:


import requests
import json

#API details
url = "http://192.168.1.100:9792/api/scan"
body = json.dumps({"service":"scan", "user_id":"1", "action":"read_all", "code":"0"})
headers = {'Content-Type': 'application/json'}

#Making http post request
response = requests.post(url, headers=headers, data=body, verify=False)

print(response.json())
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