Bas*_*tek 8 instagram swift ios13 xcode11
在 iOS 12.4 之前,将照片共享到 Instagram 提要(按照文档)的实现工作正常,但从 iOS 13 开始它不再起作用。
使用当前的实现 -UIDocumentInteractionController的 UTI 设置为"com.instagram.exclusivegram"和文件扩展名.igo- 根本没有可见的 Instagram 共享选项。当我将文件扩展名更改为.ig我可以在建议中看到 Instagram 共享选项。这种分享到提要的方式有效,但这不是预期的仅适用于 Instagram 的解决方案。
将 UTI 设置为"com.instagram.photo"不会改变任何东西。
当我点击“分享”按钮时,预期的行为是在下面看到可见的视图,而不需要额外的步骤。这可能是 Instagram 的错误,还是有其他方法可以为 iOS 13 实现它?
您应该将图像添加到照片库,然后将图像直接从它共享到 instagram
首先不要忘记将 NSPhotoLibraryAddUsageDescription 和 instagram 方案添加到您的 info.plist 中:
<key>NSPhotoLibraryAddUsageDescription</key>
<string>$(PRODUCT_NAME) wants to save pictures to your library</string>
<key>LSApplicationQueriesSchemes</key>
<array>
<string>instagram</string>
</array>
Run Code Online (Sandbox Code Playgroud)
适用于12.4和13 iOS
import UIKit
import Photos
class TestViewController: UIViewController, UIDocumentInteractionControllerDelegate {
override func viewDidLoad() {
super.viewDidLoad()
postImageToInstagram(UIImage(named: "bigImage")!)
}
func postImageToInstagram(_ image: UIImage) {
// Check if we have instagarm app
if UIApplication.shared.canOpenURL(URL(string: "instagram://app")!) {
// Requesting authorization to photo library in order to save image there
PHPhotoLibrary.requestAuthorization { status in
if status == .authorized {
UIImageWriteToSavedPhotosAlbum(image, self, #selector(self.image(_:didFinishSavingWithError:contextInfo:)), nil)
} else { print("wrong status \(status)") }
}
} else { print("Please install the Instagram application") }
}
@objc func image(_ image: UIImage, didFinishSavingWithError error: Error?, contextInfo: UnsafeRawPointer) {
if let error = error {
print(error)
return
}
let fetchOptions = PHFetchOptions()
// add sorting to take correct element from fetchResult
fetchOptions.sortDescriptors = [NSSortDescriptor(key: "creationDate", ascending: false)]
fetchOptions.fetchLimit = 1
// taking our image local Identifier in photo library to share it
let fetchResult = PHAsset.fetchAssets(with: .image, options: fetchOptions)
if let lastAsset = fetchResult.firstObject {
let url = URL(string: "instagram://library?LocalIdentifier=\(lastAsset.localIdentifier)")!
if UIApplication.shared.canOpenURL(url) { UIApplication.shared.open(url) }
else { print("Please install the Instagram application") }
}
}
}
Run Code Online (Sandbox Code Playgroud)