Azure 数据资源管理器（kusto）如何按天汇总，与“其他”一起顶？

Question

我是 Kusto 语言的新手 - 请帮助我创建查询。

这里数据集：

let T = datatable(d:datetime , s:string)
[
    datetime(2019-10-01T00:01:00.00), "A",
    datetime(2019-10-01T00:02:00.00), "A",
    datetime(2019-10-01T00:03:00.00), "A",
    datetime(2019-10-02T00:01:00.00), "A",
    datetime(2019-10-02T00:02:00.00), "A",
    datetime(2019-10-02T00:03:00.00), "A",    
    datetime(2019-10-01T00:01:00.00), "C",    
    datetime(2019-10-01T00:02:00.00), "C",
    datetime(2019-10-02T00:01:00.00), "C",
    datetime(2019-10-02T00:02:00.00), "C",
    datetime(2019-10-01T00:01:00.00), "D",        
    datetime(2019-10-02T00:01:00.00), "D",    
    datetime(2019-10-01T00:01:00.00), "E",    
    datetime(2019-10-02T00:01:00.00), "E",                                
];

我希望与其他人一起获得每个“s”字符串的前 2 个，并按天汇总。即结果需要是：

2019-10-01T00:00:00Z    A   3
2019-10-01T00:00:00Z    C   2
2019-10-01T00:00:00Z    Other   2
2019-10-02T00:00:00Z    A   3
2019-10-02T00:00:00Z    C   2
2019-10-02T00:00:00Z    Other   2

我想我以查询结束：

T
| summarize c = count() by bin(d, 1d), s
| top-nested of d by dummy0 = max(0)
| top-nested 2 of s with others = "Other" by c0 = sum(c);

但它不起作用。

请指教。

Answer 1

这是一种使用顶级嵌套执行此操作的方法，它的性能应该比您的建议更好：

let T = datatable(d:datetime , s:string)
[
    datetime(2019-10-01T00:01:00.00), "A",
    datetime(2019-10-01T00:02:00.00), "A",
    datetime(2019-10-01T00:03:00.00), "A",
    datetime(2019-10-02T00:01:00.00), "A",
    datetime(2019-10-02T00:02:00.00), "A",
    datetime(2019-10-02T00:03:00.00), "A", 
    datetime(2019-10-01T00:01:00.00), "C",    
    datetime(2019-10-01T00:02:00.00), "C",
    datetime(2019-10-02T00:01:00.00), "C",
    datetime(2019-10-02T00:02:00.00), "C",
    datetime(2019-10-01T00:01:00.00), "D",        
    datetime(2019-10-02T00:01:00.00), "D",    
    datetime(2019-10-01T00:01:00.00), "E",    
    datetime(2019-10-02T00:01:00.00), "E",                                
];
T
| summarize c = count() by bin(d, 1d), s
| top-nested of d by dummy=max(0), top-nested 2 of s with others = "Others" by _count = sum(c)
| where _count > 0 | project-away dummy