如何替换SQL Server 2005中的XML节点的一部分

Question

我想知道如何使用xquery更新SQL Server 2005中XML节点的部分文本

在以下示例中,我想将"very"替换为"excellent"

    declare @xml as xml
    set @xml = '<root><info>well hello this is a very good example</info></root>'
    declare @replacement as varchar(50)
    set @replacement = 'excellent'
    declare @search as varchar(50)
    set @search = 'very'

    set @xml.modify('replace value of (/root/info/text())[1]
                     with replace((/root/info/text())[1],sql:variable("@search"),sql:variable("@replacement"))'
        )
    select @xml

任何帮助,将不胜感激

Answer 1

由于您要替换的这个单词不是 XML 标记的内容 - 而只是该内容的一部分 - 您可能只想查看基于文本的替换选项。

如果你有这样的东西，它会起作用：

declare @xml as xml

set @xml = '<root><info>well hello this is a <rating>very good</rating> example</info></root>'

然后，您可以访问 XML 并<rating>....</rating>用其他内容替换 的内容：

declare @replacement as varchar(50)
set @replacement = 'excellent'

set 
    @xml.modify('replace value of (/root/info/rating/text())[1]
                 with sql:variable("@replacement")')

select @xml

但就目前情况而言，您可能必须获取 的文本内容<info>并对其进行文本替换：

DECLARE @xml as XML
SET @xml = '<root><info>well hello this is a very good example</info></root>'

DECLARE @newcontent VARCHAR(1000)
SELECT @newcontent = @xml.value('(/root/info/text())[1]', 'VARCHAR(1000)')

-- replace "very" with "excellent"    
SELECT @newcontent = REPLACE(@newcontent, 'very', 'excellent')

SET 
@xml.modify('replace value of (/root/info/text())[1]
                 with sql:variable("@newcontent")')

SELECT @xml