Pet*_*zov -1 java junit spring spring-boot junit5
我想编辑此代码以使用模拟服务。这段代码工作正常:
@Service
public class BinCountryCheckFilterImpl {
private RiskFilterService riskFilterService;
private Terminals terminal;
@Autowired
public BinCountryCheckFilterImpl(Terminals terminal, RiskFilterService riskFilterService) {
this.terminal = terminal;
this.riskFilterService = riskFilterService;
}
public void validateBinCountryCheckFilter(Terminals terminal) throws JAXBException, JsonProcessingException {
List<RiskFilters> filter_list = riskFilterService.findRiskFiltersByTerminalIdAndType(terminal.getId(), "BinCountryCheckFilter");
}
}
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JUnit 测试:
public class BinCountryCheckFilterImplTest {
@Test
public void testBinCountryCheckFilterImpl() throws JsonProcessingException, JAXBException {
//Arrange
RiskFilterService riskFilterService = Mockito.mock(RiskFilterService.class);
Terminals terminal = Mockito.mock(Terminals.class);
BDDMockito.given(
riskFilterService.findRiskFiltersByTerminalIdAndType(anyInt(), anyString()))
.willReturn(riskFiltersList);
int expectedInt = 11;
String expectedString = "BinCountryCheckFilter";
when(terminal.getId()).thenReturn(expectedInt);
BinCountryCheckFilterImpl binCountryCheckFilterImpl =
new BinCountryCheckFilterImpl(terminal, riskFilterService);
//Act
binCountryCheckFilterImpl.validateBinCountryCheckFilter();
//Assert
then(riskFilterService)
.should()
.findRiskFiltersByTerminalIdAndType(expectedInt, expectedString);
}
}
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此代码不起作用:
@Service
public class BinCountryCheckFilterImpl {
@Autowired
@Qualifier("riskFilterService")
private RiskFilterService riskFilterService;
public Response validateBinCountryCheckFilter(Merchants merchant, Contracts contract, Terminals terminal,
PaymentTransaction message, HttpServletRequest request) throws JAXBException, JsonProcessingException {
...........
}
}
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出于某种原因riskFilterService,当我运行 JUnit 测试时为 null。有什么方法可以通过 JUnit 测试正确实现服务吗?就我而言,我不想terminal从构造函数调用,而是从 Java 方法validateBinCountryCheckFilter(...)和riskFilterServiceAutowired 服务调用。
单例 bean BinCountryCheckFilterImpl 不能将每个请求的值终端作为一个字段,即在部署代码但它与 JUnit 测试一起工作时作为构造函数上的参数。如果终端值必须作为方法参数传递,则 JUnit 代码将不会运行。
请你给点建议好吗?
我假设您使用的是 JUnit4。最简单的方法是使用MockitoJUnitRunner这样的:
@RunWith(MockitoJUnitRunner.class)
public class BinCountryCheckFilterImplTest {
@InjectMocks
private BinCountryCheckFilterImpl binCountryCheckFilter;
@Mock
private RiskFilterService riskFilterService;
@Test
public void testBinCountryCheckFilterImpl() {
// test content
}
}
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要使用JUnit 5,你会改变@RunWith(MockitoJUnitRunner.class)对@ExtendWith(MockitoExtension.class)。当然,其他类似的东西@Test也需要来自 JUnit 5。但是,Mockito@InjectMocks和@Mock注释与 JUnit 4 相同。
但是,您也可以在使用org.springframework.test.util.ReflectionTestUtils模拟服务调用构造函数后使用 Spring设置字段。我更喜欢第一种方式而不是反射,但这更接近您当前的代码。
riskFilterService = Mockito.mock(RiskFilterService.class);
binCountryCheckFilter = new BinCountryCheckFilterImpl();
ReflectionTestUtils.setField(binCountryCheckFilter, "riskFilterService", riskFilterService);
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