您可以使用该random模块并使用列表理解填充嵌套列表
import random
low = 0
high = 10
cols = 10
rows = 5
[random.choices(range(low,high), k=cols) for _ in range(rows)]
[[5, 7, 1, 0, 6, 5, 9, 2, 5, 6],
[9, 2, 3, 0, 6, 7, 0, 6, 6, 3],
[2, 7, 9, 2, 4, 5, 5, 9, 9, 4],
[2, 6, 7, 8, 5, 1, 4, 4, 4, 4],
[9, 2, 8, 4, 5, 2, 0, 1, 2, 1]]
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对于嵌套的浮点数列表,您可以将每个浮点数映射range为float:
choices = list(map(float, range(low,high)))
[random.choices(choices , k=cols) for _ in range(rows)]
[[0.0, 3.0, 9.0, 1.0, 5.0, 3.0, 7.0, 4.0, 2.0, 4.0],
[5.0, 8.0, 7.0, 7.0, 7.0, 2.0, 9.0, 8.0, 2.0, 6.0],
[3.0, 3.0, 1.0, 9.0, 2.0, 8.0, 7.0, 2.0, 9.0, 7.0],
[7.0, 8.0, 1.0, 2.0, 0.0, 6.0, 7.0, 6.0, 0.0, 9.0],
[3.0, 3.0, 3.0, 1.0, 7.0, 8.0, 3.0, 9.0, 2.0, 8.0]]
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