通过在c#中反序列化将xml转换为List

Question

我有一个xml文件,我试图通过反序列化填充我的列表与数据.

我的xml在这里

<?xml version="1.0" ?>
<CustomerQueryRs>
    <CustomerRet>
        <ListID>6BE0000-1159990808</ListID>
        <Name>+ Blaine Bailey</Name>
        <FullName>+ Blaine Bailey</FullName>
        <Phone>866-855-0800</Phone>
    </CustomerRet>
    <CustomerRet>
        <ListID>9BA0000-1165353294</ListID>
        <Name>+ Brian Boyd</Name>
        <FullName>+ Brian Boyd</FullName>
        <Phone>203-245-1877</Phone>
    </CustomerRet>
        <CustomerRet>
        <ListID>9280000-1164147562</ListID>
        <Name>+ Brian Leahy</Name>
        <FullName>+ Brian Leahy</FullName>
        <Phone>508-341-0955</Phone>
    </CustomerRet>
</CustomerQueryRs>

我在这里给出完整的代码.我只是不明白为什么我的代码不起作用...我的代码中缺少什么......它没有给出错误但列表没有填充.所以请告诉我需要在代码中纠正哪个区域.

[XmlTypeAttribute(AnonymousType = true)]
public class CustomersData
{
    [XmlArray(ElementName = "CustomerQueryRs")]
    [XmlArrayItem(ElementName = "CustomerRet")]
    public List<Customer> Customers { get; set; }

    public CustomersData()
    {
        Customers = new List<Customer>();
    }

}

public class Customer
{
    [XmlElement(ElementName = "ListID")]
    public string ListID { get; set; }

    [XmlElement(ElementName = "Name")]
    public string Name { get; set; }

    [XmlElement(ElementName = "FullName")]
    public string FullName { get; set; }

    [XmlElement(ElementName = "Phone")]
    public string Phone { get; set; }
}

这是我的desirialization代码

private object DeserialzeXml(string xml)
    {
        var xmlSer = new XmlSerializer(typeof(CustomersData), new XmlRootAttribute("CustomerQueryRs"));
        var stringReader = new StringReader(xml);
        return xmlSer.Deserialize(stringReader);
    }

请帮忙......

Answer 1

这应该工作:

[XmlElement("CustomerRet")]
public List<Customer> Customers { get; set; }

一个完整的例子:

[XmlTypeAttribute(AnonymousType = true)]
public class CustomersData
{
    [XmlElement("CustomerRet")]
    public List<Customer> Customers { get; set; }

    public CustomersData()
    {
        Customers = new List<Customer>();
    }
}

public class Customer
{
    [XmlElement(ElementName = "ListID")]
    public string ListID { get; set; }

    [XmlElement(ElementName = "Name")]
    public string Name { get; set; }

    [XmlElement(ElementName = "FullName")]
    public string FullName { get; set; }

    [XmlElement(ElementName = "Phone")]
    public string Phone { get; set; }
}

class Program
{
    static void Main()
    {
        var xml = 
@"<?xml version=""1.0"" ?>
<CustomerQueryRs>
  <CustomerRet>
    <ListID>6BE0000-1159990808</ListID>
    <Name>+ Blaine Bailey</Name>
    <FullName>+ Blaine Bailey</FullName>
    <Phone>866-855-0800</Phone>
  </CustomerRet>
  <CustomerRet>
    <ListID>9BA0000-1165353294</ListID>
    <Name>+ Brian Boyd</Name>
    <FullName>+ Brian Boyd</FullName>
    <Phone>203-245-1877</Phone>
  </CustomerRet>
  <CustomerRet>
    <ListID>9280000-1164147562</ListID>
    <Name>+ Brian Leahy</Name>
    <FullName>+ Brian Leahy</FullName>
    <Phone>508-341-0955</Phone>
  </CustomerRet>
</CustomerQueryRs>";
        var serializer = new XmlSerializer(typeof(CustomersData), new XmlRootAttribute("CustomerQueryRs"));
        using (var stringReader = new StringReader(xml))
        using (var reader = XmlReader.Create(stringReader))
        {
            var result = (CustomersData)serializer.Deserialize(reader);
            Console.WriteLine(result.Customers[1].FullName);
        }
    }
}