使用AS从CTE中选择？SQL Server 2008

Question

我正在尝试将PostgreSQL转换为SQL Server.但是这个查询不起作用.

我究竟做错了什么？我尝试在WITH之前添加分号但没有运气.

   SELECT 
      member_a AS you, member_b AS mightknow, shared_connection,
      CASE
         WHEN (n1.member_job_country = n2.member_job_country AND n1.member_job_country = n3.member_job_country) THEN 'country in common'
         WHEN (n1.member_unvan_id = n2.member_unvan_id AND n1.member_unvan_id = n3.member_unvan_id) THEN 'unvan in common'
         ELSE 'nothing in common'
      END AS reason
   FROM (
      WITH transitive_closure(member_a, member_b, distance, path_string, direct_connection) AS
        (SELECT 
             member_a, member_b, 1 AS distance,
             CAST(member_a as varchar(MAX)) + '.' + CAST(member_b as varchar(MAX)) + '.' AS path_string,
             member_b AS direct_connection
         FROM Member_Contact_Edges
         WHERE member_a = 45046 -- set the starting node

         UNION ALL

         SELECT 
             tc.member_a, e.member_b, tc.distance + 1,
             CAST(tc.path_string as varchar(MAX)) + CAST(e.member_b as varchar(MAX)) + '.' AS path_string,
             tc.direct_connection
         FROM Member_Contact_Edges AS e
         JOIN transitive_closure AS tc ON e.member_a = tc.member_b
         WHERE tc.path_string NOT LIKE '%' + CAST(e.member_b as varchar(MAX)) + '.%'
         AND tc.distance < 2
        )

   SELECT
       member_a, member_b,direct_connection AS shared_connection
   FROM transitive_closure
   WHERE distance = 2
  ) AS youmightknow
  LEFT JOIN Members AS n1 ON youmightknow.member_a = n1.memberID
  LEFT JOIN Members AS n2 ON youmightknow.member_b = n2.memberID
  LEFT JOIN Members AS n3 ON youmightknow.shared_connection = n3.memberID
  WHERE (n1.member_job_country = n2.member_job_country 
         AND n1.member_job_country = n3.member_job_country)
        OR (n1.member_unvan_id = n2.member_unvan_id 
            AND n1.member_unvan_id = n3.member_unvan_id);

我得到的错误:

消息156,级别15,状态1,行11
关键字"WITH"附近的语法不正确.
消息319,级别15,状态1,行11
关键字'with'附近的语法不正确.如果此语句是公用表表达式,xmlnamespaces子句或更改跟踪上下文子句,则必须以分号终止先前的语句.
消息102,级别15,状态1,行34
'''附近的语法不正确.

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提前致谢

Answer 1

CTE声明需要排在最前面.您还可以使用逗号声明和连接多个CTE,而不是混合CTE和派生表.

尝试

;WITH 
/*First CTE declaration*/
transitive_closure(member_a, member_b, distance, path_string, direct_connection) 
AS
(   
     ...
),
/*Second CTE declaration*/
youmightknow AS
(
SELECT member_a, member_b,direct_connection AS shared_connection
FROM transitive_closure
WHERE distance = 2
)        
SELECT member_a AS you,
...
FROM youmightknow