在我的 Azure DevOps YAML 管道中，如何将一堆阶段转换为作业矩阵？

Question

我有一组看起来像这样的工作阶段。

- stage: UpdateWoW
  dependsOn: Install
  variables:
  - group: ${{ parameters.StageVars }}
  jobs:
  - template: UpdateApp.yml
    parameters:
      AppName: WoW
      Project: oxygen

- stage: UpdateSCII
  dependsOn: Install
  variables:
  - group: ${{ parameters.StageVars }}
  jobs:
  - template: UpdateApp.yml
    parameters:
      AppName: SCII
      Project: carbon

- stage: UpdateDIII
  dependsOn: Install
  variables:
  - group: ${{ parameters.StageVars }}
  jobs:
  - template: UpdateApp.yml
    parameters:
      AppName: DIII
      Project: xenon

我只是用两个不同的参数调用同一个模板。我想用矩阵清理它。当涉及模板时，记录的示例并没有给我太多内容。我已经尝试了一些变体，但到目前为止，我注入矩阵或包含策略的任何地方都是“意想不到的”。

- stage: UpdateApps
  dependsOn: Install
  variables:
  - group: ${{ parameters.StageVars }}
  jobs:
  - template: UpdateApp.yml
    matrix:
      wow:
        AppName: WoW
        Project: oxygen

      sc2:
        AppName: SCII
        Project: carbon

      d3:
        AppName: DIII
        Project: xenon

    parameters:
      AppName: $(AppName)
      Project: $(Project)

被调用的模板如下所示：

#UpdateApp.yml
parameters:
  AppName: $(AppName)
  Project: $(Project)

jobs:
- job:
  timeoutInMinutes: 120
  variables:
    Path: D:\games
  steps:
  - template: prep.yml $(Path) 

  - script: dostuff.cmd $(Path) ${{parameters.AppName}} ${{parameters.Project}}

  - script: domore.cmd $(Path) ${{parameters.AppName}} ${{parameters.Project}}

Answer 1

弄清楚了。矩阵出现在工作层面。舞台是这样的：

- stage: UpdateApps
  dependsOn: Install
  variables:
  - group: ${{ parameters.StageVars }}
  jobs:
  - template: UpdateApp.yml

模板：

#UpdateApp.yml

jobs:
- job:
  timeoutInMinutes: 120
  variables:
    Path: D:\games
  strategy:
    matrix:
      wow:
        AppName: WoW
        Project: oxygen

      sc2:
        AppName: SCII
        Project: carbon

      d3:
        AppName: DIII
        Project: xenon

  steps:
  - template: prep.yml $(Path) 

  - script: dostuff.cmd $(Path) $(AppName) $(Project)

  - script: domore.cmd $(Path) $(AppName) $(Project)