假设我有$rows = 4,并且$cols = 4;,如何以螺旋顺序创建包含16个元素的数组,例如:
1, 2, 3, 4,
12,13,14,5,
11,16,15,6,
10,9, 8, 7,
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我的解决方案非常详细,因为您的目的是检查它并了解它是如何工作的.
<?php
/**
* Creates a 2D array with the given dimensions,
* whose elements are numbers in increasing order
* rendered in a 'spiral' pattern.
*/
function createSpiral($w, $h) {
if ($w <= 0 || $h <= 0) return FALSE;
$ar = Array();
$used = Array();
// Establish grid
for ($j = 0; $j < $h; $j++) {
$ar[$j] = Array();
for ($i = 0; $i < $w; $i++)
$ar[$j][$i] = '-';
}
// Establish 'used' grid that's one bigger in each dimension
for ($j = -1; $j <= $h; $j++) {
$used[$j] = Array();
for ($i = -1; $i <= $w; $i++) {
if ($i == -1 || $i == $w || $j == -1 || $j == $h)
$used[$j][$i] = true;
else
$used[$j][$i] = false;
}
}
// Fill grid with spiral
$n = 0;
$i = 0;
$j = 0;
$direction = 0; // 0 - left, 1 - down, 2 - right, 3 - up
while (true) {
$ar[$j][$i] = $n++;
$used[$j][$i] = true;
// Advance
switch ($direction) {
case 0:
$i++; // go right
if ($used[$j][$i]) { // got to RHS
$i--; $j++; // go back left, then down
$direction = 1;
}
break;
case 1:
$j++; // go down
if ($used[$j][$i]) { // got to bottom
$j--; $i--; // go back up, then left
$direction = 2;
}
break;
case 2:
$i--; // go left
if ($used[$j][$i]) { // got to LHS
$i++; $j--; // go back left, then up
$direction = 3;
}
break;
case 3:
$j--; // go up
if ($used[$j][$i]) { // got to top
$j++; $i++; // go back down, then right
$direction = 0;
}
break;
}
// if the new position is in use, we're done!
if ($used[$j][$i])
return $ar;
}
}
/**
* Assumes the input is a 2D array.
*/
function print2DGrid($array) {
foreach ($array as $row) {
foreach ($row as $col) {
print sprintf("% 2d ", $col);
}
print "\n";
}
}
$width = 12;
$height = 8;
print2DGrid(createSpiral($width, $height));
?>
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在这里它正在运行,给出以下输出:
0 1 2 3 4 5 6 7 8 9 10 11
35 36 37 38 39 40 41 42 43 44 45 12
34 63 64 65 66 67 68 69 70 71 46 13
33 62 83 84 85 86 87 88 89 72 47 14
32 61 82 95 94 93 92 91 90 73 48 15
31 60 81 80 79 78 77 76 75 74 49 16
30 59 58 57 56 55 54 53 52 51 50 17
29 28 27 26 25 24 23 22 21 20 19 18
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希望这可以帮助.