React Native - 类型错误：null 不是对象

Question

我仍在学习 React Native，并且尝试从 API 检索数据并将其作为自定义单选按钮返回，但如果我确实调用 API，则会收到此错误：

null 不是对象（正在评估 'this.props.activities.map'）

 {this.props.activities.map((val, index) => {
    let { key, type, placeholder } = val;

    if (type === "selection") {
      var buttons = [];

      placeholder.forEach((e, index) => {
        var selectedButton = img.findButton(e, true);
        var normalButton = img.findButton(e);

        buttons.push(
          <RadioButton
            key={index}
            value={e}
            element={<Image source={selectedButton} />}
            selectedElement={<Image source={normalButton} />}
            onPress={() => this.changeSelection(key, e)}
            selected={this.state[key]["value"]}
          />
        );
      });

      var rows = [],
        columns = [];
      var i = 0;

      buttons.forEach((e, index) => {
        rows.push(e);
        i++;

        if (i === 2 || index === buttons.length - 1) {
          //max buttons per row
          i = 0;
          columns.push(
            <View key={index} style={{ flex: 1, flexDirection: "row" }}>
              {rows}
            </View>
          );
          rows = [];
          i = 0;
        }
      });

      return (
        <View key={key} style={{ flex: 1, margin: normalize(20) }}>
          {columns}
        </View>
      );
    }
  })}

'this.props.activites' 来自于此

let initialState = {
    activities: null,

};

export default function mainReducer(state = initialState, action) {
    switch (action.type) {
        case t.RECEIVE_ACT:
            return Object.assign({}, state, { actReceived: true, activities: action.activities });
        case t.EMPTY_ACT:
            return Object.assign({}, state, { actReceived: false, activities: null });
        default:
            return state;
    }
}

我想知道它是如何变成空的

Answer 1

的初始状态activities是null。因此，直到您从 api 收到响应之前，React 都会使用该值渲染这部分代码null。您可以指定activities: []为初始值，也可以在地图函数之前指定其是否为空，例如

{this.props.activities && this.props.activities.map((val, index) => {...

如果您要使用activities: []，那么您仍然可以在地图之前进行检查，尽管它是可选的但仍然很好，例如；

{this.props.activities.length && this.props.activities.map((val, index) => {...