SQL Server:按降序选择不同的mon-yyyy格式输出sorty

Question

我datetime在表中有一列包含以下数据:

2011-03-23
2011-04-19
2011-04-26
2011-05-26

我想选择mon-yyyy按报告日期降序排序的不同格式输出.我们需要在SQL语句中只选择一列

这个SQL有效,但我想按ReportDate列排序

SELECT  distinct SUBSTRING (convert(varchar, ReportDate, 100),1,3) +'-'+
        SUBSTRING (convert(varchar, ReportDate, 100),8,4 ) 
  FROM [EnvelopsDB].[dbo].[Envelopes]

产量

Apr-2011
Mar-2011
May-2011

这个SQL给出了一个错误:

SELECT  distinct SUBSTRING (convert(varchar, ReportDate, 100),1,3) +'-'+
        SUBSTRING (convert(varchar, ReportDate, 100),8,4 ) 
  FROM [EnvelopsDB].[dbo].[Envelopes]
  order by ReportDate

错误:

如果指定了SELECT DISTINCT,则消息145,级别15,状态1,行2 ORDER BY项目必须出现在选择列表中.

什么是获得我需要的输出的最佳SQL查询？

Answer 1

with testdata as
(
  select cast('2011-03-23' as datetime) as d
union all
  select cast('2011-04-19' as datetime)
union all
  select cast('2011-04-26' as datetime)
union all
  select cast('2011-05-26' as datetime)
)
SELECT DATENAME(month,d)+'-'+DATENAME(year,d)
FROM testdata
GROUP BY DATEPART(year,d), DATEPART(month,d), DATENAME(month,d),DATENAME(year,d)
ORDER BY DATEPART(year,d), DATEPART(month,d)

SELECT DATENAME(month,ReportDate)+'-'+DATENAME(year,ReportDate)
FROM [EnvelopsDB].[dbo].[Envelopes]
GROUP BY DATEPART(year,ReportDate), DATEPART(month,ReportDate), DATENAME(month,ReportDate),DATENAME(year,ReportDate)
ORDER BY DATEPART(year,ReportDate), DATEPART(month,ReportDate)