出现错误：解析方法过度指定。指定回调*或*返回 Promise；不是都

Question

当我运行我的函数时，它给了我错误：Resolution method is overspecified. Specify a callback *or* return a Promise; not both.任何人都可以检查我的代码，并帮助解决这个问题吗？我在这里放置了完整的代码

it('Get Organizations', async function (done) {
        let user_permission = await commonService.getuserPermission(logged_in_user_id,'organizations','findAll');
        let api_status = 404;
        if(user_permission) { 
            api_status = 200;
        }

        let current_token = currentResponse['token'];
        old_unique_token = current_token;

        chai.request(app)
            .post('entities')
            .set('Content-Type', 'application/json')
            .set('vrc-access-token', current_token)
            .send({ "key": "organizations", "operation": "findAll" })
            .end(function (err, res) {
                currentResponse = res.body;
                expect(err).to.be.null;
                expect(res).to.have.status(api_status);
                done();
            }); 

    });

Answer 1

done定义单元测试函数时不要使用async，而是简单地像平常一样从异步方法中返回，在await接收以下请求后chai-http：

it('Get Organizations', async function () {
        let user_permission = await commonService.getuserPermission(logged_in_user_id,'organizations','findAll');
        let api_status = 404;
        if(user_permission) { 
            api_status = 200;
        }

        let current_token = currentResponse['token'];
        old_unique_token = current_token;

        await chai.request(app) // note 'await' here
            .post('entities')
            .set('Content-Type', 'application/json')
            .set('vrc-access-token', current_token)
            .send({ "key": "organizations", "operation": "findAll" })
            .then(function (err, res) { // not 'then', not 'end'
                currentResponse = res.body;
                expect(err).to.be.null;
                expect(res).to.have.status(api_status);
            }); 

    });

测试运行器将await自动执行您的函数。