从Unix时间戳创建NSDate

Question

如何从Unix时间戳创建NSDate？

channel.startDate = [NSDate dateWithTimeIntervalSince1970:
(NSTimeInterval)[channelJson objectForKey:@"broadcastStartedTime"]];

我收到此错误:

104:错误:指向预期浮点值的指针值

channels.startDate是一个NSDate*.键"broadcastStartedTime"的值是Number转换为NSNumber或NSDecimalNumber通过SBJson解析器库的Javascript .

Answer 1

试试这个:

NSNumber *startTime = channelJson[@"broadcastStartedTime"];
channel.startDate = [NSDate dateWithTimeIntervalSince1970:[startTime doubleValue]];

您的值被捕获在指针类型中NSNumber.该dateWithTimeIntervalSince1970方法期望一个原语NSTimeInterval(在封面下,是一个原语double).

Answer 2

用途-doubleValue:

// NSTimeInterval is just a typedef for double
NSTimeInterval interval = [[channelJson objectForKey:@"broadcastStartedTime"] doubleValue];
channel.startDate = [NSDate dateWithTimeIntervalSince1970:interval];