单击通知按钮未在颤动中打开应用程序

Question

我已经集成了用于通知的 firebase-messaging 插件，但单击通知应用程序如果在后台或被杀死，则不会打开。我想在单击通知时打开应用程序。

下面是我的代码

    void firebaseCloudMessagingListeners() {
      FirebaseMessaging _firebaseMessaging = new FirebaseMessaging();
      _firebaseMessaging.getToken().then((token){
        print(token);
      });

     _firebaseMessaging.requestNotificationPermissions(
            const IosNotificationSettings(sound: true, badge: true, alert: true));
        _firebaseMessaging.onIosSettingsRegistered
            .listen((IosNotificationSettings settings) {
          print("Settings registered: $settings");
        });

      _firebaseMessaging.configure(
        onMessage: (Map<String, dynamic> message) async {
          _showNotificationWithDefaultSound(message['notification']['body']);

          print('on message $message');
          return;
        },
        onResume: (Map<String, dynamic> message) async {
          _showNotificationWithDefaultSound(message['data']['body']);
          print('on message $message');
          return;
        },

        onLaunch: (Map<String, dynamic> message) async {
          _showNotificationWithDefaultSound(message['data']['body']);
          print('on message $message');
        },
      );
    }

    _showNotificationWithDefaultSound(message) async {
      FlutterLocalNotificationsPlugin flutterLocalNotificationsPlugin =
          new FlutterLocalNotificationsPlugin();

      var android = new AndroidInitializationSettings('@mipmap/ic_launcher');
      var ios = new IOSInitializationSettings();
      var initSettings = new InitializationSettings(android, ios);
      flutterLocalNotificationsPlugin.initialize(initSettings,
          onSelectNotification: onSelectNotification);

      var android1 = new AndroidNotificationDetails(
          'channel id', 'channel NAME', 'channel DESCRIPTION',
          importance: Importance.Max, priority: Priority.High, ticker: 'ticker');

      var ios1 = new IOSNotificationDetails();
      var platform = new NotificationDetails(android1, ios1);
      await flutterLocalNotificationsPlugin
          .show(0, message, 'App Notification!', platform, payload: message);
    }

Answer 1

您需要在AndroidManifest.xml中添加

  <intent-filter>
      <action android:name="FLUTTER_NOTIFICATION_CLICK" />
      <category android:name="android.intent.category.DEFAULT" />
  </intent-filter>

然后，您需要在 Firebase 通知的数据正文中发送 click_action:FLUTTER_NOTIFICATION_CLICK ，如下所示：

  DATA='{
  "notification": {
    "body": "this is a body",
    "title": "this is a title"        
  },
  "data": {
    "att1": "value..", 
    "att2": "value..",        
    "click_action": "FLUTTER_NOTIFICATION_CLICK",
  },
  "to": "<FCM TOKEN>"
}'

当你的应用程序被杀死时，如果你点击通知，则会调用 onLaunch 方法，你必须获取 message['data'] 来获取参数。

在这里查看更多信息：https ://stackoverflow.com/a/48405551/7105694