'(req: Request, res: IResponse, next: NextFunction) => void' 类型的参数不能分配给 express.js 类型的参数'PathParams'

Sli*_*lim 4 node.js express typescript

我正在创建一个路由处理程序,我想将它添加到我的路由中:

import { Request, Response, NextFunction } from "express";

interface IResponse extends Response {
  error: (code: number, message: string) => Response;
  success: (code: number, message: string, result: any) => Response
}
const routeHandler = (req: Request, res: IResponse, next: NextFunction) => {
  res.error = (statusCode: number, errorMessage: string) => res.status(statusCode).json(errorMessage);
  res.success = (statusCode: number, message: string, result: any) => res.status(statusCode).json({
    message,
    result
  });
  return next();
};

export default routeHandler;
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当我将此处理程序添加到路由索引文件时:

import { Router } from "express";
import routeHandler from "../utils/helpers";

const routes = Router();
routes.use(routeHandler);

export default routes;

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我收到此错误:

No overload matches this call.
  The last overload gave the following error.
    Argument of type '(req: Request, res: IResponse, next: NextFunction) => void' is not assignable to parameter of type 'PathParams'.
      Type '(req: Request, res: IResponse, next: NextFunction) => void' is missing the following properties from type '(string | RegExp)[]': pop, push, concat, join, and 25 more.ts(2769)
index.d.ts(55, 5): The last overload is declared here.
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小智 10

Express 对您的界面一无所知IResponse。所以方法无法匹配。

要实现您的想法,请使用模块扩充

import { Request, Response, NextFunction } from "express";

declare module 'express-serve-static-core' {
    interface Response {
        error: (code: number, message: string) => Response;
        success: (code: number, message: string, result: any) => Response
    }
}

const routeHandler = (req: Request, res: Response, next: NextFunction) => {
    res.error = (statusCode: number, errorMessage: string) => res.status(statusCode).json(errorMessage);
    res.success = (statusCode: number, message: string, result: any) => res.status(statusCode).json({
        message,
        result
    });
    return next();
};

export default routeHandler;
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  • 为什么它不知道这件事?他的“IResponse”扩展了“Response” (4认同)